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suter [353]
2 years ago
15

Assume the acceleration of the object is a(t) = −9.8 meters per second per second. (Neglect air resistance.) A baseball is throw

n upward from a height of 3 meters with an initial velocity of 10 meters per second. Determine its maximum height. (Round your answer to two decimal places.)
Physics
1 answer:
wel2 years ago
8 0

Answer:8.1 m

Explanation:

Given

ball is launched from height of 3 m

initial velocity u=10 m/s

considering the ball is thrown vertically upward

Using v^2-u^2=2 as

where,

u=initial velocity

v=final Velocity

a=acceleration

s=distance

At maximum height final velocity will be zero

v^2-u^2=2 gs

0-10^2=2(-9.8)\cdot h

h=5.10 m

Therefore maximum height w.r.t ground is 3+5.10=8.10 m

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A - 6 meters a second ( 6m/s)

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1pt A cannon fires a 5-kg ball horizontally from a
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Answer: Both cannonballs will hit the ground at the same time.

Explanation:

Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.

then the acceleration equation is only on the vertical axis, and can be written as:

a(t) = -(9.8 m/s^2)

Now, to get the vertical velocity equation, we need to integrate over time.

v(t) = -(9.8 m/s^2)*t + v0

Where v0 is the initial velocity of the object in the vertical axis.

if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s

and:

v(t) = -(9.8 m/s^2)*t

Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)

And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.

You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)

7 0
3 years ago
Methods to determine the specific heat capacity of a substance​
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The heat capacity and the specific heat

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Batman (mass = 96.1 kg) jumps straight down from a bridge into a boat (mass = 458 kg) in which a criminal is fleeing. The veloci
MariettaO [177]

Answer:

The velocity of the boat after the batman lands in it is +9.26 m/s

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision.

Note: The collision between the Batman and the boat is an inelastic collision.

m'u'+mu = V(m+m').................... Equation 1

Where m' = mass of the Batman, u' = initial velcoity of the batman, m = mass of the boat, u = initial velocity of the boat, V = common velocity.

make V the subject of equation 1

V = (m'u'+mu)/(m+m')............... Equation 2

Given: m' = 96.1 kg, u' = 0 m/s, m = 458 kg, u = +11.3 m/s.

Substitute these values into equation 2

V = [(96.1×0)+(458×11.2)]/(96.1+458)

V = 5129.6/554.1

V = +9.26 m/s

8 0
3 years ago
A car is moving down the street at 53km/h. A child suddenly runs into the street. If it takes the driver 0.75 sec to react and a
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Answer:

11.04m

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Convert hours to seconds: 53m/h / 3600 =14.72m/s

14.72 (.75) = 11.04

8 0
2 years ago
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