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suter [353]
2 years ago
15

Assume the acceleration of the object is a(t) = −9.8 meters per second per second. (Neglect air resistance.) A baseball is throw

n upward from a height of 3 meters with an initial velocity of 10 meters per second. Determine its maximum height. (Round your answer to two decimal places.)
Physics
1 answer:
wel2 years ago
8 0

Answer:8.1 m

Explanation:

Given

ball is launched from height of 3 m

initial velocity u=10 m/s

considering the ball is thrown vertically upward

Using v^2-u^2=2 as

where,

u=initial velocity

v=final Velocity

a=acceleration

s=distance

At maximum height final velocity will be zero

v^2-u^2=2 gs

0-10^2=2(-9.8)\cdot h

h=5.10 m

Therefore maximum height w.r.t ground is 3+5.10=8.10 m

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Fiesta28 [93]

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To solve this problem we will apply the concepts related to the conservation of momentum. Momentum can be defined as the product between mass and velocity. We will depart to facilitate the understanding of the demonstration, considering the initial and final momentum separately, but for conservation, they will be later matched. Thus we will obtain the value of the mass. Our values will be defined as

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