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3 years ago

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Assume the acceleration of the object is a(t) = −9.8 meters per second per second. (Neglect air resistance.) A baseball is throw

n upward from a height of 3 meters with an initial velocity of 10 meters per second. Determine its maximum height. (Round your answer to two decimal places.)

1 answer:

wel3 years ago

8 0

Answer:8.1 m

Explanation:

Given

ball is launched from height of 3 m

initial velocity $u=10 m/s$

considering the ball is thrown vertically upward

Using $v^2-u^2=2 as$

where,

u=initial velocity

v=final Velocity

a=acceleration

s=distance

At maximum height final velocity will be zero

$v^2-u^2=2 gs$

$0-10^2=2(-9.8)\cdot h$

$h=5.10 m$

Therefore maximum height w.r.t ground is $3+5.10=8.10 m$

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While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme

djverab [1.8K]

Considering that while traveling on a road with a<u> final speed of 15 m/s</u>, and an<u> initial speed of 24 m/s</u>, with a given time <u>of 12 seconds.</u>

To calculate the acceleration, we apply the following formula:

α = Vf - Vo/t

We add our data into the formula and solve:

α = 15 m/s - 24 m/s/12 sec

α = -0.75 m/s²

Therefore, the acceleration of the car is -0.75 m/s².

<h2>Skandar</h2>

4 0

2 years ago

A beam of light from a laser illuminates a glass how long will a short pulse of light beam take to travel the length of the glas

Eduardwww [97]

Answer:

The time of short pulse of light beam is $2.37\times10^{-9}\ sec$

Explanation:

Given that,

A beam of light from a laser illuminates a glass.

Suppose, the length of piece is $L=25.21\times10^{-2}\ m$

Index of refraction is 2.83.

We need to calculate the speed of light pulse in glass

Using formula of speed

$v=\dfrac{c}{\mu}$

Put the value into the formula

$v=\dfrac{3\times10^{8}}{2.83}$

$v=1.06\times10^{8}\ m/s$

We need to calculate the time of short pulse of light beam

Using formula of velocity

$v=\dfrac{d}{t}$

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{25.21\times10^{-2}}{1.06\times10^{8}}$

$t=2.37\times10^{-9}\ sec$

Hence, The time of short pulse of light beam is $2.37\times10^{-9}\ sec$

3 0

4 years ago

A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has

Anuta_ua [19.1K]

Answer:

$T_0 = 338.916 Degree\ celcius$

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

Thermal properties remain constant, transfer of heat by radiation is negligible.

from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

$\lambda_1 = 1.5708 and A_1= 1.2732$

The fourier number is

$t = \frac{\alpha t}{l^2} = \frac{97.1\times 10^{-6} \times 15}{0.05^2} = 0.5826$

Temperature at center after 15 second of heating

$\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}$

$T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}$

$T_0 = (25 - 475) 1.2732 e^{-1.5708^2 \times 0.5826} + 475 = 356 degree celcius$

$T_0 = 338.916 Degree\ celcius$

8 0

3 years ago

A monochromatic light falls on two narrow slits that are 4.50 um apart. The third destructive fringes which are 35° apart were f

STatiana [176]

Answer:

y = 1.19 m and λ = 8.6036 10⁻⁷ m

Explanation:

This is a slit interference problem, the expression for destructive interference is

d sin θ = m λ

indicate that for the angle of θ = 35º it is in the third order m = 3 and the separation of the slits is d = 4.50 10⁻⁶ m

λ = d sin θ / m

let's calculate

λ = 4.50 10⁻⁶ sin 35 /3

λ = 8.6036 10⁻⁷ m

for the separation distance from the central stripe, we use trigonometry

tan θ= y / L

y = L tan θ

the distance L is measured from the slits, it indicates that the light source is at x = 0.30 m from the slits

L = 2 -0.30

L = 1.70 m

let's calculate

y = 1.70 tan 35

y = 1.19 m

3 0

3 years ago

Convert 9/4 hours into minutes

Eduardwww [97]

Am guessing;

9/4 × 60/1 =135

5 0

3 years ago