The llamas average acceleration from 15 to 20 seconds is 5
Answer:
110 rev
Explanation:
Given:
v₀ = 32 m/s
v = 0 m/s
a = -2.25 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (32 m/s)² + 2 (-2.25 m/s²) Δx
Δx = 228 m
The circumference of the tires is 2π × 0.32 m = 2.01 m. Therefore:
228 m × (1 rev / 2.01 m) = 110 rev
The study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.
<h3>What is nanomachining?</h3>
The expression nanomachining makes reference to the study of nanometric machines (nanomachines) and related materials, which can be achieved by different approaches including sensor-based strategies related to acoustic auditive phenomena.
In conclusion, the study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.
Learn more about nanomachines here:
brainly.com/question/20875598
#SPJ1
Question: Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.
Answer:
1.29 m/s²
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
Given: v = 13 m/s, u = 35 m/s, t = 17 s.
a = (13-35)/17
a = -22/17
a = -1.29 m/s²
Hence the deceleration of the car is 1.29 m/s²
Answer:
the acceleration of the rocket is: a=vemΔmΔt−g a = v e m Δ m Δ t − g .
Explanation:
I answered this before.
hope this helps! :)