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Eva8 [605]
3 years ago
10

A balloon that has been rubbed on wool has a negative charge. When the balloon is held over—but not touching—some bits of paper,

some of the bits jump up to the balloon. Why does the paper move?
Physics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

This process is known as static electricity

Explanation:

When balloon is rubbed on the wool , a negative charge is usually formed. When the balloon is then held over—but not touching—some bits of paper, some of the bits jump up to the balloon. The bits which jump up to the balloon are positive charged and we know that unlike charges attract.

This process explains static electricity which is when the charges on a material are not in a balanced state.

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In the alpha decay of Francium-221, what daughter element is produced? (You may need to refer to the periodic table in the lesso
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The atomic number (number of protons) of the Francium is 87, and since in the decay it loses 2 protons, the atomic number of the daughter nucleus should be 85. Looking at the periodic table ,this corresponds to Astatine, and therefore this is the element produced in the alpha decay of Francium-221.
Moreover, the mass number (number of protons+neutrons) decreases by 4 (because an alpha particle carries 2 protons+2 neutrons), therefore in the reaction the mass number will decrease from 221 to 217. 
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You serve a volley ball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has_______ energy. Can
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An object is dropped from a height H. During the final second of its fall, it traverses a distance of 53.2 m. What was H? An obj
Serhud [2]

Answer:

H = 171.90 m

Explanation:

given data

distance = 53.2 m

height = H

to find out

height H

solution

we know height is here H = \frac{1}{2} gt^2    ......................1

here t is time and a is acceleration

so

we find t first

we know during time (t -1) s , it fall distance (H - 53.2) m

so equation of distance

H - 53.2 = \frac{1}{2} g (t-1)^2

H - 53.2 = \frac{1}{2} g (t^2-2t+1)

H - 53.2 = \frac{1}{2} gt^2-gt+\frac{1}{2} g     ................2

now subtract equation 2 from equation 1 so we get

H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)

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so from equation 1

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H = 171.90 m

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