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Eva8 [605]
3 years ago
10

A balloon that has been rubbed on wool has a negative charge. When the balloon is held over—but not touching—some bits of paper,

some of the bits jump up to the balloon. Why does the paper move?
Physics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

This process is known as static electricity

Explanation:

When balloon is rubbed on the wool , a negative charge is usually formed. When the balloon is then held over—but not touching—some bits of paper, some of the bits jump up to the balloon. The bits which jump up to the balloon are positive charged and we know that unlike charges attract.

This process explains static electricity which is when the charges on a material are not in a balanced state.

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If a football player does 39000 J of work, how much power does the football player exert in 5 minutes
Drupady [299]

Answer:

Power = 130 watt

Explanation:

Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:

power = \frac{work (J)}{Time (s)}

In this example, power is calculated as follows:

Work = 39000 J

Time = 5 minutes

converting the time from minutes to seconds:

1 minute = 60 seconds

∴ 5 minutes = 60 × 5 = 300 seconds

\therefore power = \frac{39000}{300} \\power = 130 watt

N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹

6 0
3 years ago
What does the word resolution mean in the sentence "By 1915, the British Roentgen Society had adopted a resolution to protect pe
iris [78.8K]
Resolution in this sentence refers to a solution to the problem 
5 0
3 years ago
You're in a car that gets 37 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and
Sergeu [11.5K]

Answer:

Required diameter of hose pipe = 0.2864 mm

Solution:

From the continuity eqn, the fluid flow rate is given by:

Av = \frac{V}{t}

where

A = cross-sectional area = \pi r^{2}

r = hose pipe radius

v = velocity of gas

Also, v = \frac{displacement, d}{time, t}

Using:

1 gallon = 3.854 l

1 mile = 1609.34 m

1 m^{3} = 1000 l

Therefore,

A\frac{d}{t} = \frac{V}{t}

\pi r^{2} = \frac{V}{d}

\pi r^{2} = \frac{(1 gal).(\frac{3.7854 l}{gal}).(\frac{10^{- 3} m^{3}}{l})}{37 miles(\frac{1609.34 m}{miles})}

6.357\times 10^{- 8} = \pi r^{2}

r^{2} = 2.024\times 10^{- 8}

r = 1.423\times 10^{- 4} m = 0.1423 mm

The diameter of the hose pipe = 2r = 2\times 1.423\times 10^{- 4}

The diameter of the hose pipe = 2.846\times 10^{- 4} m = 0.2846 mm

4 0
3 years ago
A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov
Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

4 0
3 years ago
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Which of the following facts about electromagnetic radiation has made it possible for scientists to gather information about Ven
sukhopar [10]

Answer:

C. Infrared and radio waves can pass through very dense materials without interference.

Explanation:

It was my study island question.

6 0
3 years ago
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