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Agata [3.3K]
3 years ago
13

Calcula la energía cinética der un vehículo de 1860kg 1ue se mueve a 50km/h​

Physics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

Kinetic energy of the vehicle is

K = 1.79 \times 10^5 J

Explanation:

Kinetic Energy of the vehicle is given as

K = \frac{1}{2}mv^2

now we have

m = 1860 kg

v = 50 km/h

v = 50 \times \frac{5}{18}

v = 13.89 m/s

now we have

K = \frac{1}{2}(1860)(13.89)^2

K = 1.79 \times 10^5 J

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While traveling along a highway a driver slows from 32 m/s and comes to a stop with an acceleration of -6 m/s2. How long did it
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Answer: 6s

Explanation:

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----------------

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Two identical tiny spheres of mass m =2g and charge q hang from a non-conducting strings, each of length L = 10cm. At equilibriu
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Answer:

0.247 μC

Explanation:

As both sphere will be at the same level at wquilibrium, the direction of the electric force will be on the x axis. As you can see in the picture below, the x component of the tension of the string of any of the spheres should be equal to the electric force of repulsion. And its y component will be equal to the weight of one sphere. We can use trigonometry to find the components of the tensions:

F_y:  T_y - W = 0\\T_y = m*g = 0.002 kg *9.81m/s^2 = 0.01962 N

T_y = T_*cos(50)\\T = \frac{T_y}{cos(50)} = 0.0305 N

T_x = T*sin(50) = 0.0234 N

The electric force is given by the expression:

F = k*\frac{q_1*q_2}{r^2}

In equilibrium, the distance between the spheres will be equal to 2 times the length of the string times sin(50):

r = 2*L*sin(50) = 2 * 0.1m * sin(50) 0.1532 m

And k is the coulomb constan equal to 9 *10^9 N*m^2/C^2. q1 y q2 is the charge of each particle, in this case, they are equal.

F_x = T_x - F_e = 0\\T_x = F_e = k*\frac{q^2}{r^2}

q = \sqrt{T_x *\frac{r^2}{k}} = \sqrt{0.0234 N * \frac{(0.1532m)^2}{9*10^9 N*m^2/C^2} } = 2.4704 * 10^-7 C

O 0.247 μC

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