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OlgaM077 [116]
3 years ago
15

Listening to your favorite radio station involves which area of physics?

Physics
1 answer:
lukranit [14]3 years ago
8 0

If I'm not mistaken the answer would be c, vibrations and wave phenomena, because when sound waves hit your ear they go through it to your brain and your mind translates these vibrations to sound. I hope my answer helped you out.

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In the diagram, the wavelength is shown by :
MAXImum [283]

Answer:

i think the anwer is C

Explanation:

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4 years ago
What was the runoff from precipitation on the property for areas with vegetation and roofed or paved areas over the past four mo
puteri [66]

Answer:

Higher percentage of runoff water is absorbed by the vegetation whereas 100 % of water runoff on the roofed area.

Explanation:

Higher percentage of runoff water is absorbed by the vegetation and very little amount of runoff water is received on the end of vegetative cover while on the other hand, 100 percent of precipitation water runoff on the surface of roofed or paved area because no water is absorbed by the roof due to its solid surface. The percentage of runoff depends on the factors such as rainfall intensity, slope, soil water storage capacity, and infiltration rate.

5 0
3 years ago
An object travels at constant velocity of 3 m/s for a time period of 7.15 s. What is its displacement over this time?
son4ous [18]

Hi there!

We can use the following equation for constant velocity:

\large\boxed{d = vt}

d = displacement (m)

v = velocity (m/s)

t = time (s)

Plug in the givens:

d = 3 * 7.15 = \boxed{21.45 m}

5 0
3 years ago
In a roller coaster, a car has X joules of potential energy when it is resting at the top of the hill. The car moves downhill an
natita [175]
"At the bottom, the car has X joules of mechanical energy" is the one among the following choices given in the question that <span>the law of conservation of energy predict about the car. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer helped you.</span>
4 0
3 years ago
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: t=\frac{D_{A}}{v_{B}-v_{A}}

              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

x=x_{0}+vt

where

x_{0} is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is D_{A}.

The equation will be:

x_{A}=D_{A}+v_{A}t

Car B started at the starting line. So, its equation is

x_{B}=v_{B}t

Part A: When they meet, both car are at "the same position":

D_{A}+v_{A}t=v_{B}t

v_{B}t-v_{A}t=D_{A}

t(v_{B}-v_{A})=D_{A}

t=\frac{D_{A}}{v_{B}-v_{A}}

Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

Part B: With the meeting time, we can determine the position they will be:

x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )

x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

5 0
3 years ago
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