Answer:
8
Step-by-step explanation:
To find the mean, you add up all the numbers and divide it by the total number of numbers. So 4+5+7+8+11+13 is 48. There are 6 numbers. So 48/6=8.
Answer: 
Step-by-step explanation:
To find the inverse of a function start by replacing f(x) with x and replace the original x with y.

Now solve for y

Finally, replace y with the inverse of f(x), 
The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)
The distance between both lighthouses is 5783.96 m
I've added an attachment that represents the scenario.
From the attachment, we have:

Convert to degrees





Convert to degrees



So, the measure of angle S is:
---- Sum of angles in a triangle


The required distance is distance AB
This is calculated using the following sine formula:

Where:

So, we have:

Make AB the subject


Hence, the distance between both lighthouses is 5783.96 m
Read more about bearing and distance at:
brainly.com/question/19017345
Answer:



Step-by-step explanation:
<u>Given:</u>



<u>Solve for </u>
<u> in the 1st equation:</u>



<u>Substitute the value of </u>
<u> into the 2nd equation and solve for </u>
<u>:</u>






<u>Substitute the value of </u>
<u> into the 3rd equation and solve for </u>
<u>:</u>






<u>Plug </u>
<u> into the solved expression for </u>
<u> and evaluate to solve for </u>
<u>:</u>



<u>Plug </u>
<u> into the solved expression for </u>
<u> and evaluate to solve for </u>
<u>:</u>




Therefore:


