A bike accelerates uniformly(from rest to a speed of 7 m/s over a distance of 40 m. Determine
1 answer:
Answer:
Explanation:
The bike's acceleration can be found by using the following suvat equation:
where
v is the final velocity of the bike
u is the initial velocity
a is the acceleration
s is the distance covered
For the bike in the problem,
u = 0
v = 7 m/s
d = 40 m
Solving the equation for a, we find the acceleration:
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Answer:
359 g Mn
General Formulas and Concepts:
- Dimensional Analysis
- Reading the Periodic Table of Elements
Explanation:
<u>Step 1: Define</u>
6.53 mol Mn
<u>Step 2: Find conversion</u>
1 mol Mn = 54.94 g Mn
<u>Step 3: Dimensional Analysis</u>
<u /> = 358.758 g Mn
<u>Step 4: Simplify</u>
<em>We are given 3 sig figs.</em>
358.758 g Mn ≈ 359 g Mn
Answer:
sin 2θ = 1 θ=45
Explanation:
They ask us to prove that the optimal launch angle is 45º, for this by reviewing the parabolic launch equations we have the scope equation
R = Vo² sin 2θ / g
Where R is the horizontal range, Vo is the initial velocity, g the acceleration of gravity and θ the launch angle. From this equation we see that the sine function is maximum 2θ = 90 since sin 90 = 1 which implies that θ = 45º; This proves that this is the optimum angle to have the maximum range.
We calculate the distance traveled for different angle
R = vo² Sin (2 15) /9.8
R = Vo² 0.051 m
In the table are all values in two ways
Angle (θ) distance R (x)
0 0 0
15 0.051 Vo² 0.5 Vo²/g
30 0.088 vo² 0.866 Vo²/g
45 0.102 Vo² 1 Vo²/g
60 0.088 Vo² 0.866 Vo²/g
75 0.051 vo² 0.5 Vo²/g
90 0 0
See graphic ( R Vs θ) in the attached ¡, it can be done with any program, for example EXCEL
