Answer:
269 m
45 m/s
-58.6 m/s
Explanation:
Part 1
First, find the time it takes for the package to land. Take the upward direction to be positive.
Given (in the y direction):
Δy = -175 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(-175 m) = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 5.98 s
Next, find the horizontal distance traveled in that time:
Given (in the x direction):
v₀ = 45 m/s
a = 0 m/s²
t = 5.98 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (45 m/s) (5.98 s) + ½ (0 m/s²) (5.98 s)²
Δx = 269 m
Part 2
Given (in the x direction):
v₀ = 45 m/s
a = 0 m/s²
t = 5.98 s
Find: v
v = at + v₀
v = (0 m/s²) (5.98 s) + (45 m/s
v = 45 m/s
Part 3
Given (in the y direction):
Δy = -175 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-175 m)
v = -58.6 m/s
Answer:
a)
b) north edge will rise up
Explanation:
torque on the coil is given as

where N is number of loop = 9 loops
i is current = 7.80 A
-B -earth magnetic field = 
A- area of circular coil


A =0.015 m2
PUTITNG ALL VALUE TO GET TORQUE


b) north edge will rise up
Answer:
if we double the distance the energy stored will be doubled also
Explanation:
The energy stored in a capacitor is given as
Energy stored =1/2(cv²)
Or
= 1/2(Qv)
Where c = capacitance
Q= charge
But the electric field is expressed as
E= v/d
where v= voltage
d= distance
v=Ed
Substituting into any equation above say
Energy stored =1/2(Qv)
Substituting v=Ev
Energy stored =1/2(QEd)
From the equation above it shows that if we double the distance The energy stored will be doubled also