5. In which image below is the most work being wasted as heat?

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does

alina1380 [7]

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is 1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| = 1x10⁻⁶/9800

|Q| = 1.02 x 10⁻⁹ Coulomb

c) No of electrons = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

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6 0

1 year ago

Introduces una masa de 80g en una probeta con 60cm cúbicos de agua y el nivel sube hasta 75cm cúbicos. qué densidad tiene la mas

ExtremeBDS [4]

Answer:

$d=5.33\ gr/cm^3$

Explanation:

<u>Densidad</u>

La densidad de una masa m que ocupa un volumen v se define como:

$\displaystyle d=\frac{m}{V}$

Tenemos que una masa de 80 gr hace que un volumen de agua se desplace desde 60 cm3 hasta 75 cm3, es decir, el volumen propio de la masa es m = 75 - 60 = 15 cm3.

Con esta información se calcula la densidad:

$\displaystyle d=\frac{80\ gr}{15\ cm^3}$

Operando:

$\boxed{d=5.33\ gr/cm^3}$

4 0

3 years ago

1. a) What equal amount of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitationa

Paul [167]

Answer:

A) q = 5.714 × 10^(13) C

B) Because from a above, F_e = F_g and so r² canceled out in the formulas

C) m_t = 5.964 × 10⁴ kg

Explanation:

For the gravitational attraction of the earth and moon to be neutralized, the electrostatic force must be equal to the gravitational force i.e F_e = F_g

Now, F_e = kq²/r² and F_g = GmM/r²

Equating them and making q the subject, we arrive at;

q = √(GmM/k)

Where;

G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²

m is mass of moon = 7.36 × 10^(22) kg

M is mass of earth = 5.98 × 10^(24) kg

k is coulombs constant = 8.99 x 10^(9) N.m²/c²

q = √(6.67 × 10^(-11) × 7.36 × 10^(22) × 5.98 × 10^(24)/8.99 x 10^(9))

q = 5.714 × 10^(13) C

B) We don't need the lunar distance because from a above, F_e = F_g and so r² canceled out in the formulas.

C) The number of protons is given by the formula;

n = q/e

Where, e is charge of the proton = 1.6 × 10^(-19) C

n = (5.714 × 10^(13))/(1.6 × 10^(-19))

n = 3.57125 × 10^(32)

Total mass of these protons is given by the formula;

m_t = nm_p

Where m_p is mass of a single proton = 1.67 × 10^(-27) kg

m_t = 3.57125 × 10^(32) × 1.67 × 10^(-27)

m_t = 5.964 × 10⁴ kg

5 0

3 years ago

How is desert pavement formed?

mihalych1998 [28]

Desert pavement or commonly called stone or stony pavement is a type of desert surface that is covered with pebbles and stone tight and intertwined. Many of these layers form a type of pavement known as mosaic. When the particles begin to be stacked between different natural agents such as rain, gravity and animals compact the layers and generates a layer that allows the pavement not to erode. Basically runoff and deflation eliminate silt and clay, leaving thicker particles behind.

The correct answer is A.

5 0

2 years ago

Four point charges each having charge Q are located at the corners of a square having sides of length a.

Murljashka [212]

Answer:

Explanation:

Given

Four Point charges are Placed at the corner of a square with side length a

Length of diagonal $a\sqrt{2}$