5. In which image below is the most work being wasted as heat?

T or f :static electricity constantly flows in the same direction

Kazeer [188]

Answer:

False

because I got that question and I gotted right

6 0

3 years ago

To analyze the motion of a body that is traveling along a curved path, to determine the body's acceleration, velocity, and posit

DiKsa [7]

To solve this problem we will apply the kinematic equations of linear motion and centripetal motion. For this purpose we will be guided by the definitions of centripetal acceleration to relate it to the tangential velocity. With these equations we will also relate the linear velocity for which we will find the points determined by the statement. Our values are given as

$R = 350ft$

$a_t = 1.1ft/s^2$

PART A )

$a_c = \frac{V^2}{R}$

$a_c = \frac{V^2}{350}$

Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $5.25ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$5.25 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$27.5625 = 1.21 + \frac{v^4}{122500}$

$v=42.3877ft/s$

Now calculate the angular velocity of the motorcycle

$v = r\omega$

$42.3877 = 350\omega$

$\omega = 0.1211rad/s$

Calculate the angular acceleration of the motorcycle

$a_t = r\alpha$

$1.1 = 350\alpha$

$\alpha = 3.1428*10^{-3}rad/s^2$

Calculate the time needed by the motorcycle to reach an acceleration of

$5.25ft/s^2$

$\omega = \alpha t$

$0.1211 = 3.1428*10^{-3}t$

$t = 38.53s$

PART B) Calculate the velocity of the motorcycle when the net acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

PART C)

Calculate the radial acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a_r = \frac{v^2}{R}$

$a_r = \frac{21.5^2}{350}$

$a_r =1.3207ft/s^2$

Calculate the net acceleration of the motorcycle when the velocity of the motorcycle is $21.5ft/s$

$a = \sqrt{a_t^2+a_r^2}$

$a = \sqrt{(1.1)^2+(1.3207)^2}$

$a = 1.7187ft/s^2$

PART D) Calculate the maximum constant speed of the motorcycle when the maximum acceleration of the motorcycle is $6.75ft/s^2$

$a = \sqrt{a_t^2+a_r^2}$

$6.75 = \sqrt{(1.1)^2+(\frac{v^2}{350})^2}$

$45.5625 = 1.21 + \frac{v^4}{122500}$

$v=48.2796ft/s$

3 0

3 years ago

Fill in the blank with the appropriate numbers for both electrons and bonds(considering that single bonds are counted as one, do

tekilochka [14]

Answer:

1.Fluorine is having 7 number of electrons and 1 makes bond.

Electronic configuration - 1S² 2S² 2P⁵

1 electron need to get in stable states 2P⁶.

2.Oxygen is having 6 balance electron and 2 makes bonds.

Electronic configuration - 1S² 2S² 2P⁴

2 electron need to get in stable states 2P⁶.

3.Nitrogen is having 5 balance electron and 3 makes bonds.

Electronic configuration - 1S² 2S² 2P³

3 electron need to get in stable states 2P⁶.

4. Carbon having 4 balance electron and 4 makes bonds.

Electronic configuration - 1S² 2S² 2P²

4 electron need to get in stable states 2P⁶.

3 0

3 years ago

For an object that’s in static equilibrium which of the following statements must be true? Check all that apply.

Kobotan [32]

The statements that are held true with regards to the static equilibrium of bodies are:

The net torque acting on the object must equal zero

The net torque on the object does not have to be zero if the net force on the object is zero

Furthermore, when a body is in a state of static equilibrium, the summation of all forces, either vertically or horizontally, must be equal to zero.

5 0

3 years ago

Read 2 more answers

When connected to a battery, a lightbulb glows brightly. If the battery is reversed and reconnected to the bulb, the bulb will g

BartSMP [9]

If the battery is reversed and reconnected to the bulb, the bulb will glow with the same brightness. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that you were looking for and it has actually come to your help.

5 0

4 years ago