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Bad White [126]
3 years ago
11

At 1:00 P.M., the air temperature was 78°F, and air pressure was 30.0 inches of mercury with partly cloudy skies. By 4:00 P.M.,

the temperature dropped to 62°F, and the pressure dropped to 29.5 inches of mercury. Which best predicts the weather for later that afternoon? pls help im about to get killed by my teacher giving out brainiest to fastest answer THAT GOES WITH DA QUESTIONNN
Chemistry
2 answers:
bonufazy [111]3 years ago
7 0
I suppose it would be rain shower :)
vlabodo [156]3 years ago
5 0
The 4:00 time because later that afternoon would be later in the day
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N2 reacts with hydrogen gas according to the following equation:
slega [8]

Answer:

Mass = 51 g

Explanation:

Given data:

Mass of nitrogen = 41.93 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂      →       2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 41.93 g/ 28 g/mol

Number of moles = 1.5 mol

now we will compare the moles of nitrogen and ammonia.

                N₂          :           NH₃

                  1          :           2

                1.5         :         2/1×1.5 = 3 mol

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 3 mol × 17 g/mol

Mass = 51 g

6 0
2 years ago
Name one way igneous rock is different from metamorphic rock.
nasty-shy [4]

Answer:

Metamorphic rock is classified by texture and composition. The texture of a metamorphic rock can be either foliated and appear layered or banded, or non-foliated and appear uniform in texture without banding. Foliated rocks contain many different kinds of minerals, but non-foliated rocks contain only one main mineral, which contributes to their more uniform appearance.  Igneous rocks are classified according to mode of occurrence, texture, mineralogy, chemical composition, and the geometry of the igneous body.

Explanation:

6 0
3 years ago
Which molecule will have a double covalent bond?<br> #3 #5 &amp; #6
KatRina [158]

Answer:the CO2 molecule has an excess of electron

4 0
2 years ago
Five ?L of a 10-to-1 dilution of a sample were added to 5mL of Bradford reagent. The absorbance at 595 nm was 0.78 and,according
Tomtit [17]

Answer:

0.03g/mL

Explanation:

Given parameters include:

Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL

Dilution factor = 10-to-1

The absorbance at 595 nm was 0.78

Mass of the diluted sample = 0.015 mg

We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.

So, to determine the concentration of the diluted sample, we have:

concentration of diluted sample = \frac{mass}{volume}

= \frac{0.015 mg}{ 5 \alpha L}   (where ∝ was use in place of μ in the expressed fraction)

= 0.003 mg/μL

The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:

protein concentration of the original solution = 10 × concentration of the diluted sample.

= 10  × 0.003 mg/μL

= 0.03 mg/μL

= \frac{0.03*10^{-3g}}{10^{-3}mL}

= 0.03g/mL

Hence, the protein concentration of the original solution is known to be  0.03g/mL

8 0
2 years ago
Consider the diagram below
Artyom0805 [142]
Energy of the reactants would be correct
5 0
2 years ago
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