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brilliants [131]

4 years ago

9

At the Last Chance Filling Station, gas costs $1.60 a gallon. Trevor paid $32.00 to fill his tank. How many gallons of gas did h

e buy? Explain please
Brainliest to the best and explaining/clear answer

1 answer:

BigorU [14]4 years ago

8 0

he used twenty gallons

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Find the 7th term of a geometric sequence with t1=5 and r = -2.

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4 years ago

In this equation which number is the divisor ? .48 \. .4=1.2

RSB [31]

0.4 is the divisor, or whichever number is under the fraction. This is because the denominator of any fraction is always the divisor of the numerator of the fraction.

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3 years ago

Which equation represents the value of x? x=100−y2−−−−−−−√ x=10+y2 x=10−y x=y2+100−−−−−−−√ Right triangle A B C with angle B as

Nostrana [21]

Answer:

Therefore the required value of x,

$x=\sqrt{(100-y^{2})}$

Step-by-step explanation:

Given:

ΔBC is a Right Angle Triangle at ∠ B = 90°

As ∠ B = 90° , AC will be the Hypotenuse

AC = 10 = Hypotenuse

BC = y = Longer leg ( say )

AB = x = Shorter leg ( say )

To Find :

x = ?

Solution:

In Right Angle Triangle Δ ABC , By Pythagoras Theorem we get

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Substituting the given values we get

$10^{2}= x^{2}+y^{2} \\\\x^{2}=100-y^{2} \\\\\textrm{square rooting on both the side we get}\\\\x=\sqrt{(100-y^{2})}\\\therefore x=\sqrt{(100-y^{2})}\ \textrm{ which is the required value of x}$

Therefore the required value of x,

$x=\sqrt{(100-y^{2})}$

8 0

3 years ago

How do i find the median in this question.

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Step-by-step explanation:

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3 years ago

Verify the identitiy:

Advocard [28]

Answer:

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

$\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$

But 1- cos²x = sin²x

Hence we will replace 1- cos²x by sin²x

$\frac{sinx}{1-cos x}$ = $\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}$ = $\frac{sinx + sinx cosx}{1-cos^{2}x }$ = $\frac{sinx+sinxcosx}{sin^{2}x }$

= $\frac{sinx}{sin^{2}x }$ + $\frac{sinxcosx}{sin^{2}x }$

= $\frac{1}{sinx}$ + $\frac{cosx}{sinx}$

= $cosecx$ + $cot x$

$\frac{sinx}{1-cos x}$ = $cosecx$ + $cot x$

Note that;

$\frac{1}{sinx}$ = $cosecx$

$\frac{cosx}{sinx}$ = $cot x$

6 0

4 years ago