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I am Lyosha [343]
3 years ago
8

why do yall think it is ok to judge ppl based on how they look bc from my point of view i dont think its ok i think ppl are beau

tiful in there own way
Physics
2 answers:
yaroslaw [1]3 years ago
4 0

Answer:

hgggkwhhsvshwhhwbejshsbehe

Semmy [17]3 years ago
3 0

Answer:

true!

Explanation:

I am happy to see some THINGS like this!

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At temperatures above roughly 800 °c, calcium carbonate will decompose. write and balance the equation for this reaction. phase
Lady_Fox [76]
CaCO3 ---->  CaO +  CO2 

hope it helps!

8 0
4 years ago
Read 2 more answers
A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of
sasho [114]

Answer:

a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m

b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m

Explanation:

(a) Radiowave wavelength= λ = c/f

As we know, Radiowave speed in the air = c = 3 x 10^8 m/s

f = frequency = 604 kHz = 604 x 10^3 Hz

Hence, wavelength = (3x10^8/604x10^3) m

λ = 496.69 m

So the height of the antenna BROADCASTING AT 604 kHz =  λ /4 = (496.69/4) m

= 124.17 m

(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz  (1kHZ = 1000 Hz)

Hence, wavelength =  λ = (3 x 10^8/1710 x 10^3) m

 λ= 175.44 m

So, height of the antenna =  λ /4 = (175.44/4) m

= 43.86 m  

5 0
3 years ago
A 10 N board of uniform density is 5 meters long. It is supported on the left by a string bearing a 3 N upward force. In order t
NikAS [45]

Answer:

C.\frac{25}{7}m

Explanation:

We are given that

Weight of board=w=10 N

Length of board=L=5 m

Tension in the string=T=3 N

Applied upward force=F=7 N

We have to find the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.

Let r be the distance at which its left wedge would they need to place this force in order for the board to be in static equilibrium.

The board is uniform therefore, the center of board is the mid- point of board.

Therefore, the lever arm of weight=r_1=\frac{L}{2}=\frac{5}{2}m

Now, the torque exerted by the weight of the board

\tau_1=Force\times perpendicular\;distance=10\times \frac{5}{2}=25 N

The torque exerted  by applied force=\tau_2=7\times r=7r

In static equilibrium

The sum of rotational forces=0

\tau_1+\tau_2=0

The two rotational force act in opposite direction therefore,

\tau_2=-7r

Substitute the values

25-7r=0

7r=25

r=\frac{25}{7}m

Hence, option C is true.

7 0
3 years ago
Beryllium has a nucleus composed of protons and neutrons. Given the data, how many neutrons are in a typical Beryllium nucleus?
shepuryov [24]
Beryllium has a mass number of 9 and 4 protons.  To find the number of neutrons you need to subtract the number of protons from the mass number.  so...
neutrons = mass - # protons
neutrons = 9 - 4 = 5
6 0
3 years ago
Read 2 more answers
Fossil fuels are burned, transferring their chemical potential energy to heat energy. How are nuclear power stations different?
labwork [276]

Answer:

fossil fuels are natural and limited, nuclear is man made and more toxic

Explanation:

6 0
3 years ago
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