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VikaD [51]
3 years ago
6

If earth's axis was tilted 45 degrees at what latitudes

Physics
1 answer:
givi [52]3 years ago
7 0
23.5 DEGREES is the answer. 
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A mass slider m = 0.200 kg rests on a frictionless horizontal air rail connected to a spring with a force constant k = 5.00 N /
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3 years ago
A particular interaction force does work wint inside a system. the potential energy of the interaction is u. which equation rela
larisa86 [58]

ΔU = -Wint

Consdier the work of of interaction is W =m*g*h - equation -1

and the Potential energy U.

Final Potential energy Uf =0 , And the Initial Potential Energy Ui =m*g*h

<span>Now we will write the equation for a Change in Potential energy ΔU,</span>

ΔU = Uf - Ui

= 0-m*g*h

<span>  ΔU = -m*g*h --Equation 2</span>

Now compare the both equation

<span>Wint = -ΔU</span>

we can rewrite the above equation

ΔU = -W.

<span>So our Answer is ΔU = -W. .</span>

<span> </span>

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3 years ago
You are a member of an alpine rescue team and must project a box of supplies, with mass m, up an incline of constant slope angle
AlekseyPX

Answer:

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

Explanation:

When we push the box from the bottom of the incline towards the top then by work energy theorem we can say that

Work done by all the forces = change in kinetic energy of the system

- mgh - F_f (s) = 0 - \frac{1}{2}mv^2

here we know that

F_f = \mu_k mg cos\theta

also we know that the length of the incline is given as

s = \frac{h}{sin\theta}

now we have

- mgh - \mu_k mgcos\theta(\frac{h}{sin\theta}) = -\frac{1}{2}mv^2

so we have

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

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3 years ago
How would you best define moving charges
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