Answer:
<h2>The angular velocity just after collision is given as</h2><h2>Explanation:
As per given figure we know that there is no external torque about hinge point on the system of given mass
So here we will have
now we can say
so we will have
Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass
So we can use angular momentum conservation about the hinge point
Answer: 230.50 m
Explanation:
We have the following information:
the barometric reading at the top of the building
the barometric reading at the bottom of the building
density of air
density of mercury
gravity
And we need to find the height of the building.
In order to approach this problem, we will firstly use the following equations to find the pressure at the top of the building and the perssure at the bottom
:
(1)
(2)
From (1): (3)
From (2): (4)
Having the pressures at the top and the bottom of the building, we can calculate the variation in pressure :
(5)
(6)
On the other hand, we have a column of air with a cross-section area and the same height of the building, lets name it
.
As pressure is defined as the force exerted on a specific area
, we can write:
(7)
If we isolate we have:
(8)
Also, the force gravity exerts on this column of air (its weight) is:
(9)
Knowing the density of air is: (10)
where the volume of air can be written as: (11)
Substituting (1) in (10):
(12)
Isolating :
(13)
Substituting (13) in (9):
(14)
Matching (8) and (14)
(15)
Isolating :
(16)
Substituting the known and calculated values:
(17)
Finally:
This is the height of the building