Answer:
least distance= 13mm
ratio of the lattice = 1 : 0.71 : 0.58
Explanation:
given λ₁ = 650nm = 650×10⁻⁹m, λ₂ = 500nm = 500×10⁻⁹m
Answer:
1.44 x 10⁻⁶ C
Explanation:
= charge on one sphere
= charge on other sphere
= Total charge on the two spheres = 40 μC
=
= 40 x 10⁻⁶
= (40 x 10⁻⁶) -
eq-1
= distance between the two spheres = 50 cm = 0.50 m
= magnitude of force between the two spheres = 2.0 N
Magnitude of force between the two spheres is given as


= 1.44 x 10⁻⁶ C
Answer: 3.12 * 10^12 F ( 3.12 pF)
Explanation: To calculate this capacitor of two hollow, coaxial, iron cylinders, we have to determine the potental differente between them and afeter that to use C=Q/ΔV
The electric field in th eregion rinner<r<router
By using the Gaussian law
∫E*ds=Q inside/εo
E*2*π*rinner^2*L= Q /εo
E=Q/(2*π*εo*r^2)
[Vab]=\int\limits^a_b {E} \, dr
where a and b are the inner and outer radii.
Then we have:
ΔV= 2*k*(Q/L)* ln (b/a)
replacing the values and using that C=Q/ΔV
we have:
C= L/(2*k*ln(b/a)=0.17/(2*9*10^9*3.023)=3.12 pF
Flow of electric charge in a wire requires " ELECTRONS "
Angel ! You have a formula, and you have an example that's
completely worked out. The ONLY POSSIBLE reason that you
could still need help is that you're letting math scare you.
I'll do 'A' for you, 'B' most of the way, and get 'C' set up.
If THAT's not enough for you to run with and finish them all,
then you and I should both be embarrassed.
Write the formula on the wall:
°F = (9/5) °C + 32°
A). Convert 35° C °F = (9/5)(35°) + 32°
(9/5)(35) = 63 °F = 63° + 32°
°F = 95°
____________________________________
B). Convert 80°F to °C
The formula: °F = (9/5) °C + 32°
°F = 80 80 = (9/5)°C + 32
Subtract 32 from each side: 48 = (9/5)°C
Multiply each side by 5 : 240 = (9) C
Now you take over:
_________________________________________
C). Convert 15°C to °F.
The formula: °F = (9/5) °C + 32°
°C = 15 °F = (9/5) 15° + 32
(9/5) (15) = 27
Go ! °F =