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Blababa [14]
3 years ago
15

What is the largest four subsystems?​

Physics
1 answer:
AnnZ [28]3 years ago
5 0

Explanation:

Everything in Earth's system can be placed into one of four major subsystems: land, water, living things, or air. These four subsystems are called "spheres." Specifically, they are the "lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air).

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2. Light waves of the wavelength of 650 nm and 500 nm produce interference fringes on a screen at a distance of 1m from a double
satela [25.4K]

Answer:

least distance= 13mm

ratio of the lattice = 1 : 0.71 : 0.58

Explanation:

given λ₁ = 650nm = 650×10⁻⁹m,  λ₂ = 500nm = 500×10⁻⁹m

5 0
3 years ago
Each of two small non-conducting spheres is charged positively, the combined charge being 40 μC. When the two spheres are 50 cm
Phantasy [73]

Answer:

1.44 x 10⁻⁶ C

Explanation:

q_{1} = charge on one sphere

q_{2} = charge on other sphere

q = Total charge on the two spheres = 40 μC

q_{1}+ q_{2} = q

q_{1}+ q_{2} = 40 x 10⁻⁶

q_{1} = (40 x 10⁻⁶) - q_{2}                                   eq-1

r = distance between the two spheres = 50 cm = 0.50 m

F = magnitude of force between the two spheres = 2.0 N

Magnitude of force between the two spheres is given as

F = \frac{k q_{1} q_{2}}{r^{2}}

2.0 = \frac{(9\times 10^{9}) ((40\times 10^{-6}) - q_{2}) q_{2}}{0.50^{2}}

q_{2} = 1.44 x 10⁻⁶ C

7 0
3 years ago
A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and
Musya8 [376]

Answer: 3.12 * 10^12 F ( 3.12 pF)

Explanation: To calculate this capacitor of two hollow, coaxial, iron cylinders, we have to determine the potental differente between them and afeter that to use C=Q/ΔV

The electric field in th eregion rinner<r<router

By using the Gaussian law

∫E*ds=Q inside/εo

E*2*π*rinner^2*L= Q /εo

E=Q/(2*π*εo*r^2)

[Vab]=\int\limits^a_b {E} \, dr

where a and b are the inner and outer radii.

Then we have:

ΔV= 2*k*(Q/L)* ln (b/a)

replacing the values and using that C=Q/ΔV

we have:

C= L/(2*k*ln(b/a)=0.17/(2*9*10^9*3.023)=3.12 pF

5 0
3 years ago
A flow of electric charge in a wire normally requires a _________.
just olya [345]
Flow of electric charge in a wire requires " ELECTRONS "
6 0
3 years ago
HELP PLEASE 
-BARSIC- [3]
Angel !  You have a formula, and you have an example that's
completely worked out.  The ONLY POSSIBLE reason that you
could still need help is that you're letting math scare you.

I'll do 'A' for you, 'B' most of the way, and get 'C' set up.
If THAT's not enough for you to run with and finish them all,
then you and I should both be embarrassed.

Write the formula on the wall:

                                   °F  =  (9/5) °C  +  32°

A).  Convert 35° C        °F  =  (9/5)(35°) + 32°

(9/5)(35) = 63              °F  =      63°      + 32°

                                     °F  =  95°
____________________________________

B).  Convert 80°F to °C 
                         The formula:    °F  =  (9/5) °C  +  32°

°F = 80                                     80  =  (9/5)°C  +  32

Subtract 32 from each side:      48 = (9/5)°C

Multiply each side by  5 :        240  =  (9) C

Now you take over:
_________________________________________

C).  Convert 15°C to °F.
                         The formula:    °F  =  (9/5) °C  +  32°

°C = 15                                      °F = (9/5) 15° + 32

(9/5) (15) = 27     
                             Go !              °F  = 

7 0
3 years ago
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