Question

An angry mob lynches a phsical teacher after receiving their grades. They throw the physics teacher off a tall building . They throw the physics teacher straight down with a velocity of 20m/s. The teacher falls for 30 seconds before landing on a stack of empty card board boxes . How high was he thrown from?

Answer 1

Answer:

5010 m

Explanation:

The vertical position of the teacher at time t can be found by using the equation:

$y(t) = h + ut+ \frac{1}{2}gt^2$

where

h is the initial height

$u = -20 m/s$ is the initial velocity (negative since it's downward)

$g=-9.8 m/s^2$ is the acceleration of gravity

t is the time

The teacher reaches the ground when y = 0, so the equation becomes

$h=-ut-\frac{1}{2}gt^2$

Substituting t = 30 s, we find the initial height:

$h=-(-20)(30)-\frac{1}{2}(-9.8)(30)^2=5010 m$