<h2>
Option A is the correct answer.</h2>
Explanation:
Here velocity of ball and bat are in opposite direction.
Velocity of ball = 40 m/s
Velocity of bat = 18 m/s
Since they are in opposite direction relative velocity is given by,
Relative velocity = 40 + 18 = 58 m/s
Distance to home plate = 18 m
We have
Displacement = Velocity x Time
18 = 58 x Time
Time = 0.3 seconds
Option A is the correct answer.
Answer:
20.2 seconds
Explanation:
The airplane (and therefore the crate) initially has no vertical velocity, so v₀ = 0 m/s.
The crate is in free fall, so a = -9.8 m/s².
The crate falls downward, so Δx = -2000 m.
Find: t, the time it takes for the crate to land.
Δx = v₀ t + ½ at²
-2000 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 20.2 s
It takes 20.2 seconds for the crate to land.
The one with the greatest mass would, when everything else is equal. I'm having trouble making out your list of choices.
Answer:
the safe's coefficient of kinetic friction on the bank floor is
Explanation:
GIven that:
Bonnie and Clyde are sliding a 325 kg bank safe across the floor to their getaway car.
So ,let assume they are sliding the bank safe on an horizontal direction
Clyde → Δ(bank safe) → Bonnie
Also; from the above representation; let not forget that the friction force is acting in the opposite direction ←
where;
=
The safe slides with a constant speed
If Clyde pushes from behind with 377 N of force while Bonnie pulls forward on a rope with 353 N of force.
Thus; since the safe slides with a constant speed if the two conditions are met; then the net force acting on the slide will be equal to zero.
SO;
Since the net force acting on the slide will be equal to zero.
Then;
Also; let and
Then;
where;
Then;
Thus; the safe's coefficient of kinetic friction on the bank floor is
For Mass
K.E = (1/2*mv^2)
Explanation:
Kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.