Answer:
Mechanical advantage = 15
Explanation:
Given the following data;
Output force = 3000N
Input force = 200N
To find the mechanical advantage;
Mechanical advantage = output force/input force
Substituting into the equation, we have 
Mechanical advantage = 3000/200
Mechanical advantage = 15
 
        
             
        
        
        
gravitational potential is directly proportional to the height of the object relative to a reference line and is given as 
PE = mgh                        
where m = mass of object , g = acceleration due to                     
gravity   and  h = height of the object above the reference line .
as the skydiver falls , its height above the ground decrease and hence the gravitational potential energy of the skydiver decrease.
as per conservation of energy , total energy of the skydiver must remain constant all the time . hence the decrease in potential energy appears as increase in kinetic energy by same amount to keep the total energy constant 
KE + PE = Total energy 
so as the skydiver falls , it gains speed and hence the kinetic energy of skydiver increase since kinetic energy is directly proportional to the square of the speed.
when the parachute opens, the skydiver experience force in upward which tries to balance the weight of the skydiver. hence the speed of the skydiver decrease until upward force becomes equal to the downward force. hence the kinetic energy decrease just after the parachute opens
 
        
             
        
        
        
Because the coefficient of friction depends on the surface
        
             
        
        
        
Answer:
The x-component of the electric field at the origin = -11.74 N/C.
The y-component of the electric field at the origin = 97.41 N/C.
Explanation:
<u>Given:</u>
- Charge on first charged particle,  
- Charge on the second charged particle,  
- Position of the first charge =  
- Position of the second charge =  
The electric field at a point due to a charge  at a point
 at a point  distance away is given by
 distance away is given by

where,
 = Coulomb's constant, having value = Coulomb's constant, having value 
 = position vector of the point where the electric field is to be found with respect to the position of the charge = position vector of the point where the electric field is to be found with respect to the position of the charge . .
 = unit vector along = unit vector along . .
The electric field at the origin due to first charge is given by

 is the position vector of the origin with respect to the position of the first charge.
 is the position vector of the origin with respect to the position of the first charge.
Assuming,  are the units vectors along x and y axes respectively.
 are the units vectors along x and y axes respectively. 

Using these values,

The electric field at the origin due to the second charge is given by

 is the position vector of the origin with respect to the position of the second charge.
 is the position vector of the origin with respect to the position of the second charge.

Using these values,

The net electric field at the origin due to both the charges is given by

Thus, 
x-component of the electric field at the origin = -11.74 N/C.
y-component of the electric field at the origin = 97.41 N/C.