The answer is A.) Gravity
Potential means position in science
Complete question
The complete question is shown on the first uploaded image
Answer:
The velocity is 
Explanation:
From the question we are told that
a = nb
The length of the minor axis of the symbol of the Federation, a circle, seen by the observer at velocity v must be equal to the minor axis(b) of the Empire's symbol, (an ellipse)
Now this length seen by the observer can be mathematically represented as

Here t is the actual length of the major axis of of the Empire's symbol, (an ellipse)
So t = a = nb
and b is the length of the minor axis of the symbol of the Federation, (a circle) when seen by an observer at velocity v which from the question must be the length of the minor axis of the of the Empire's symbol, (an ellipse)
i.e h = b
So
![[\frac{1}{n} ]^2 = 1 - \frac{v^2}{c^2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7Bn%7D%20%5D%5E2%20%3D%20%201%20-%20%20%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D)
![v^2 =c^2 [1- \frac{1}{n^2} ]](https://tex.z-dn.net/?f=v%5E2%20%3Dc%5E2%20%5B1-%20%5Cfrac%7B1%7D%7Bn%5E2%7D%20%5D)
![v^2 =c^2 [\frac{n^2 -1}{n^2} ]](https://tex.z-dn.net/?f=v%5E2%20%3Dc%5E2%20%5B%5Cfrac%7Bn%5E2%20-1%7D%7Bn%5E2%7D%20%5D)

In calculating the energy of a photon of light, we need the relationship for energy and the frequency which is expressed as:
E=hv
where h is the Planck's constant (6.626 x 10-34 J s)and v is the frequency.
E = 6.626 x 10-34 J s (<span>7.33 x 10^14 /s) = 4.857 x 10^-19 J</span>