Solve for y. Please help.

Mathematics

1 answer:

klasskru [66]4 years ago

8 0

Answer:

c) 68

Step-by-step explanation:

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My teacher gave me the brain teaser and ive been trying to figure it out can someone help she wants me to find 2 answers for it.

Masja [62]

2^5 + (4 + 3 + 1) = 40

((5 x 3) + (4 + 1)) x 2 = 40

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4 years ago

What is the equation of the line that passes through the point (-2, 7) and has a slope of zero

lorasvet [3.4K]

Answer:

y = 7 is the equation of the line that passes through the point ( -2, 7 ) and has a slope of zero.

Step-by-step explanation:

Given:

Let,

A ≡ ( x1 , y1 ) ≡ ( -2, 7 )

Slope = m = 0

To Find :

Equation of Line:

Solution:

Formula for , equation of a line passing through a point ( x1 , y1 ) and having a slope m is given by

$(y - y_{1})=m(x-x_{1})$

Now substituting the values of x1 = -2 and y1 = 7 and slope m = 0 we get,

$y-7=0\times(x--2) \\y-7=0\times (x+2)\\y-7=0\\\therefore y=7$

Which is the required equation of a line passing through the point ( -2, 7 ) and slope zero

6 0

3 years ago

Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1

mote1985 [20]

Answer:

$x^3 -x^2 -25x +25$

Step-by-step explanation:

$\text{The roots are,}~ \alpha = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25$