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fgiga [73]
3 years ago
14

Amphiphilic molecule: ___________

Chemistry
1 answer:
erica [24]3 years ago
7 0
The answer is E - have both hydrophilic and hydrophobic groups.
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Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with wate
notsponge [240]

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by K_{OW} (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one,  when it's more dissolved in water, the value is lower.

What is the partition coefficient?

  • The partition coefficient for the two-phase network comprising n-octanol and water is known as the K_{OW} value. N-Octanol-Water Partition Ratio is another name for it.
  • The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by K_{OW}. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.
  • Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique K_{OW} ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

Learn more about octanol here:

brainly.com/question/7768749

#SPJ4

8 0
1 year ago
which of these is an example of a chemical change A breaking glass B mealting ice on a windshield C burning gasoline D denting a
Nonamiya [84]

Lets do process of elimination!

A. Breaking glass - That is a psychical change because if you break it, it is still glass. It didn't change to another substance.

B. Melting ice on a windshield - During the melting process, there is no chemical change, and therefore, no new substance is created.  

C. Burning gasoline - When gas burns it usually combines with oxygen to give carbon dioxide, water etc.  It is a chemical change.

D. Denting a bumper - The bumper is still a bumper, only thing is it has a dent in it. The properties did not change, meaning no chemical change.

7 0
3 years ago
Read 2 more answers
Part IV. Limiting Reactants! A Challenge Problem!
Alexxandr [17]

Answer:

a. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

b. Fe2O3 is the limiting reactant.

c. 6.30 grams Fe

d. 52.6 %

Explanation:

Step 1: Data given

Mass of iron(III) oxide Fe2O3 = 9.00 grams

Mass of aluminium = 4.00 grams

Molar mass Fe2O3 = 159.69 g/mol

Aluminium molar mass = 26.98 g/mol

Step 2: The balanced equation

Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

Step 3; Calculate Moles

Moles = mass / molar mass

Moles Fe2O3 = 9.00 grams / 159.69 g/mol

Moles Fe2O3 = 0.0564 moles

Moles Al = 4.00 grams / 26.98 g/mol

Moles Al = 0.148 moles

Step 4: Calculate limiting reactant

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

Fe2O3 is the limiting reactant. It will completely be consumed (0.0564 moles).  Al is in excess. There will react 0.0564*2 = 0.1128 moles

There will remain 0.148 - 0.1128 = 0.0352 moles Al

Step 5: Calculate moles Fe

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

For 0.0564 moles Fe2O3 we'll have 2*0.0564 = 0.1128 moles Fe

Step 6: Mass of Fe

Mass Fe = 0.1128 moles * 55.845 g/mol

Mass Fe = 6.30 grams

Step 7: If you carried out this reaction and it actually produced 0.475 mL of molten iron (r = 6.98 g/mL), what is the percent yield of this reaction?

Density = mass / volume

Mass = density * volume

Mass = 6.98 g/mL * 0.475 mL

Mass = 3.3155 grams

Percent yield = (actual mass / theoretical mass) * 100%

Percent yield = (3.3155 /6.30 ) * 100 %

Percent yield = 52.6 %

3 0
3 years ago
Which of the following elements is a metalloid
klemol [59]
A metalloid can be:
 - Boron (B)
 - Silicon (Si)
 - Germanium ( Ge)
 - Arsenic (As) 
 - Antimony ( Sb)
 - Tellurium (Te)
 - Polonium (Po)

Hope this helps :)
6 0
3 years ago
Read 2 more answers
In order to perform a chemical reaction, 225 mL of 0.500 M lead (II) nitrate is required. How much 5.00 M stock solution is requ
vladimir1956 [14]

Answer:

what

Explanation:

what ````

4 0
3 years ago
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