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Tanzania [10]
3 years ago
9

What is the percent by mass of Fluorine in Nitrogen triflouride NF3?

Chemistry
1 answer:
Kipish [7]3 years ago
3 0

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

                    = 14 + 57

                    = 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

                       71 g of NF₃ ------------------ 100%

                       57 g of F   ------------------- x

                            x = (57 x 100)/71

                            x = 5700 / 71

                            x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

           

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Explanation:

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Knowing the chemical reaction we devise the following reasoning:

if        3 moles of H₂O produces 1 mole of CaCO₃

then  8.94 moles of H₂O produces X moles of CaCO₃

X = (8.94 × 1) / 3 = 2.98 moles of CaCO₃

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mass of CaCO₃ = 2.98 × 100 = 298 g

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