G) X=4
H) X=2
I) X=-3
J) X=2
What we need to do with this problem is multiply the amount the computer costs ($350) by the tax rate (6%). To do this, we first need to convert the percentage to a decimal, so we divide the 6 given by 100, leaving us with .06. Next, we need to multiply the $350 by the .06, giving us $21 as the amount we should be paying for sales tax. So your answer should be 2) $21.00!
Answer:
Parallel lines have the same slope, so the one with the same slope.
The square root of 10 because
sqrt(10) ^2 * 3.14 =
10*3.14 = 31.4
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
