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Ne4ueva [31]
3 years ago
11

The volume of a cube can be found using the equation V = s^3, where V is the volume and s is the measure of one side of the cube

.
A cube has a volume of 756 in^3. How do you find the length of a side?

Question 4 options:

s = cube root of 756 in.


s = 756 in.


s = 756^3 in.


s = the square root of 756 in.

Will give out brainly, please answer correctly.
You better answer correctly, because I'm giving away a lot of points.
Mathematics
2 answers:
NemiM [27]3 years ago
5 0
The cube root of 756
Fofino [41]3 years ago
4 0
It is the cube root of 756
^3 and cube root are inverse functions
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Please help!<br> Solve for x.
aalyn [17]

Answer:

1. 15.9

2. 12

3. 7.29

4. 20.8

5. 11.0

Step-by-step explanation:

We can use the Pythagorean Theorem to solve for x (a squared minus b squared equals c squared)

Example number 1 is solved by  17 squared - 6 squared equals 253

You do square root and get 15.90

Number 4 is you have to divide 24 by 2 because it is one of the sides

So it is 24 squared minus 12 squared

You find square root and get 20.80

5 0
3 years ago
The price of a dozen eggs was $1.63. The price rose m dollars. Then the price dropped $0.12 per dozen. Express the current price
Vsevolod [243]
With eggs represented by the variable "e", price represented by variable "p"
p=12e(1.63+m-0.12)
feel free to simplify
7 0
3 years ago
PLEASE HELP ME IM STUCK
Tems11 [23]

Answer:

5x^2  -3x  +9

Step-by-step explanation:

To subtract, line up the common terms.  I add a 0 term to keep the terms in line.

5x^2  + 0x  +7

- (0x^2 +3x-  2 )

------------------------


Distribute the negative sign.

5x^2  + 0x  +7

- 0x^2 -3x  + 2

------------------------

5x^2  -3x  +9

3 0
3 years ago
Read 2 more answers
Help!
TEA [102]
Multiply both sides by 10...
So u = 50/11 = 4.5454... = 4.55
5 0
4 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
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