Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Step-by-step explanation:
3x - 2x + 8 = 12; x=4
Now, Evaluate the value of x
3(4) - 2(4) + 8 = 12
12 - 8 + 8 = 12
12 + 0 = 12
12 = 12
2 x (5-2)^3
2 x (3)^3
2 x 27
54
Answer:The formula for a can be calculated by the following steps;
Step-by-step explanation:
-3a-a=4b-6b
-4a=-2b
cancelling the negative sign;
4a=2b
a=2b/4
a=b/2
r > 0 = r is greater than 0
r ≤ 8 = r is less than and equal to 8
0 ≤ r ≤ 8
