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umka21 [38]
3 years ago
15

An alcohol that contains only one -oh group can be classified as a

Chemistry
1 answer:
alexandr1967 [171]3 years ago
8 0
Alkanol [having only one oh group]
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Consider the following data for five hypothetical elements: Q, W, X, Y, and Z. Rank the elements from most reactive to least rea
aleksley [76]

Answer:

Y Q W Z X

Explanations:

The most reactive element is the element that will displace an element from it compound . The most reactive element will replace the less reactive element in it compound.

Q+ + Y Reaction occurs

Since the reaction occurs the element Y which is more reactive displaced element Q from it compound.

Q+W+ Reaction occurs

The reaction occurs, that means element Q replaces element w from it compound. Element Q is therefore more reactive than element W.

W+Z+ Reaction occurs

The reaction also occurs . This is an indication that element W replaces element Z in it compound. This means element W is very reactive than element Z.

X+Z+ No reaction

There is no reaction here. This is an indication that element X is less reactive than element Z. This is why element X can't displace element Y in it compound.

4 0
3 years ago
M
Rasek [7]

Answer:

1.They are reliable.

2.They dont vary from person to person

3 0
3 years ago
You burn 270 grams of glucose during respiration. How
BlackZzzverrR [31]

Answer:

396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.

Explanation:

To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;

C6H12O6 + 6O2 -------> 6CO2 + 6H2O

1 mole of C6H12O6 reacts to form 6 moles of CO2

Then, calculate the molar mass of the two variables;

Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol

Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol

Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles

1* 180 g of glucose yields 6 * 44 g of CO2

180 g of glucose = 264 g of CO2

If 270 g of glucose were to be used, how many grams of CO2 will be produced;

so therefore,

180 g of glucose = 264 g of CO2

270 g of glucose = x grams of CO2

x = 264 * 270 / 180

x = 71 280 / 180

x = 396 g of CO2.

In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.

8 0
3 years ago
Which of the following correctly represents the transmutation in which a curium-242 nucleus is bombarded with an alpha particle
Alekssandra [29.7K]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:

_{96}^{242}\textrm{Cm}+_4^2\textrm{He}\rightarrow _{98}^{245}\textrm{Cf}+_0^1\textrm{n}

The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.

6 0
4 years ago
Two identical bottles at the same temperature contain the same gas. If bottle B has twice the volume and contains half the numbe
yuradex [85]

Answer:

The ratio of pressure in bottle B to that of bottle A is 1 : 4

Explanation:

We'll be by calculating the pressure in both bottles. This is illustrated below below:

For A:

Temperature (T) = T

Volume (V) = V

Number of mole (n) = n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

PV = n x 0.0821 x T

Divide both side by V

P = nT0.0821/V

Therefore, the pressure, in bottle A is

PA = nT0.0821/V

For B:

Temperature (T) = the same as that of A = T

Volume (V) = twice that of A = 2V

Number of mole (n) = half that of A = ½n

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =...?

PV = nRT

P x 2V = ½n x 0.0821 x T

Divide both side by 2V

P = ½n x 0.0821 x T/2V

P = nT0.0821/4V

Therefore, the pressure in bottle B is:

PB = nT0.0821/4V

Now, we can obtain the ratio of pressure in bottle B to that of bottle A as follow:

Pressure in bottle A (PA) = nT0.0821/V

Pressure in bottle B (PB) = nT0.0821/4V

PB/PA = nT0.0821/4V ÷ nT0.0821/V

PB/PA = nT0.0821/4V x V/nT0.0821

PB/PA = 1/4

Therefore, the ratio of pressure in bottle B to that of bottle A is 1 : 4.

3 0
3 years ago
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