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umka21 [38]
3 years ago
15

An alcohol that contains only one -oh group can be classified as a

Chemistry
1 answer:
alexandr1967 [171]3 years ago
8 0
Alkanol [having only one oh group]
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A formula unit represents the simplest ratio of elements in a______of an ionic compound.
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Answer: mole

A formula unit represents the simplest ratio of elements in a mole of an ionic compound.

Explanation:

The formula unit, also known as the empirical formula, gives the simplest whole number ratio of the components of the elements in a mole of an ionic compound.

Thus, the formula unit and the molecular formula of a compound can be the same.

For example: Glucose with C6H12O6 will have a formula unit of CH2O. Thus, the simplest ratio of carbon, hydrogen and oxygen in glucose is 1:2:1

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If you need some points and are good at science help!
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region 2 and region 3

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Which nonmetal would an ion of Ca +2 most likely ionically bond within a 1:1 ratio?
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Examine the snapshot of sedimentary layers shown here. Which statements accurately describe the relationship between these organ
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2 years ago
What are the final hydrogen ion concentration and pH of a solution obtained by mixing 400mL of 0.2M NaOH with 150mL of 0.1M H3PO
dusya [7]

Explanation:

The chemical reaction equation will be as follows.

      H_{3}PO_{4} + 3NaOH \rightarrow Na_{3}PO_{4} + 3H_{2}O

In this reaction, 1 mole of H_{3}PO_{4} reacts with 3 mole NaOH. So, the number of moles of H_{3}PO_{4} present  in 150 ml of 0.1 M solution is calculated as follows.

               No. of moles = \frac{150}{1000 \times 0.1}  

                                      = 0.015 mol

As it reacts with 3 moles of NaOH. Hence, no.. of moles of NaOH are:

                           3 \times 0.015 mol

                              = 0.045 mol

So, moles of NaOH in 400 of 0.2 M NaH is as follows.

                No. of moles = \frac{400}{1000 \times 2}

                                       = 0.080 mol

Hence, no. of moles remained after the reaction are as follows.

                 (0.080 - 0.045) mol

               = 0.035 mol NaOH in 550 ml (400 ml + 150 ml)

As molarity is the no. of moles present in liter of solution. Hence, molarity of   NaOH is as follows.

     Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                    = \frac{0.035}{550}        

                   = 0.0636 M

As, [OH^{-}] = 0.0636 M. Hence, pOH will be 1.20.

As,           pH + pOH = 14

                  pH = 14 - pOH

                        = 14 - 1.20

                        = 12.80

Also, [H^{+}] = 10^{-pH}    

So,          [H^{+}] = 10^{-12.80}    

                           = 1.58 \times 10^{-13} M

Thus, we can conclude that pH of the given solution is 12.80 and its hydrogen ion concentration is 1.58 \times 10^{-13} M.

8 0
3 years ago
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