Answer: 1.3% many crosslinks as isoprene units,
Explanation:
Given:
mass pf natural rubber= 200.0g
mass of sulphur = 4.8g
molar mass of sulphur =32g/mol
molar mass of isoprene = C5H8=( 12x5) +(1x8)= 68g/mol
Solution: we first find no of moles present in each using
no of moles = 
Isoprene: 200.0g x [1mole / 68g] = 2.94moles.
Sulfur: 4.8g x [1mole / 32g] x [1 mole crosslinks / 4 moles S] = 0.0375 moles crosslinks.
to find % crosslinked units, we have
0.0375 / 2.94 = 1.3% as many crosslinks as isoprene units,
Answer:
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
Explanation:
Step 1: Data given
For the equation aA + bB ⇆ cC + dD
The equilibrium constant is [C]^c * [D]^d / [A]^a*[B]^b
Step 2: Calculate the equilibrium constant Kc
CO+3H2⇌CH4+H2O
Kc = [H2O][CH4] / [CO][H2]³
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
No icicles are water made up of atoms not cells