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ziro4ka [17]
3 years ago
13

What are the coefficients that will balance the skeleton equation below?

Chemistry
1 answer:
Vesna [10]3 years ago
5 0

Answer:

the answer is 1,3,2

Explanation:

Balance equation

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What type of reaction is shown below? Check all that apply. Ca + 2H2O → Ca(OH)2 + H2 synthesis decomposition combustion single r
Ksju [112]

The balanced reaction is

Ca + 2H2O → Ca(OH)2 + H2

Here this reaction can be compared with

A + BC  ---> AB + C

So here one reactant (A) is accepting a group which is being given by another compound (BC) however the A is not giving any group / element or ion

So this single displacement

Similarly in the given reaction

the anion OH- is only being replaced

The element Ca accepts OH- and H2O loses the same group to form new element H2

So the correct answer is

Single replacement also known as single displacement


3 0
3 years ago
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The atoms in a copper bar are held together by metallic bonding. What would happen you ran over a copper bar with a car? It woul
ludmilkaskok [199]

The answer is D.

<em>Hope this helps!</em>

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3 years ago
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State joule thomson effect
tiny-mole [99]

Answer:

In thermodynamics, the Joule–Thomson effect describes the temperature change of a real gas or liquid when it is forced through a valve or porous plug while keeping it insulated so that no heat is exchanged with the environment. This procedure is called a throttling process or Joule–Thomson process

5 0
3 years ago
What is the ph of the benzoic acid solution prior to adding sodium benzoate?
Reika [66]
The acid dissociation constant of benzoic acid is 6.5 x 10^-5. Therefore, the pH of the benzoic acid solution prior to adding sodium benzoate is:

pH = -log[Ka]
pH = -log (6.5 x 10^-5)
pH = 4.19

The pH of the benzoic acid solution is 4.19 which is acidic, but a weak acid. 

7 0
3 years ago
A 25.00 mL sample of the ammonia solution
musickatia [10]

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

3 0
3 years ago
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