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UNO [17]
3 years ago
15

The unit of entropy ?

Physics
2 answers:
Monica [59]3 years ago
6 0

Answer:

The SI unit of entropy is joules per Kalvin.

hope it helps!

mixas84 [53]3 years ago
3 0

Answer:joule per Kelvin

Explanation:

The SI unit for entropy is joule per Kelvin

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An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp
laila [671]

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

a = \frac{v^2}{r}

At constant speed, we will have;

v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

7 0
3 years ago
Which is not a step in the scientific method?
tensa zangetsu [6.8K]
A. Ask other people for their opinion. :)
5 0
3 years ago
A spring has a spring constant of 20 N/m. How much potential energy is stored in the spring as it stretched 0.20 m
makkiz [27]
The elastic potential energy (Ep) is given by Ep = \frac{1}{2}*k*x^2

Data: 
Ep = ? (Joule)
k = 20 N/m
x (displacement) = 0.20 m

Solving:
Ep = \frac{1}{2}*k*x^2
Ep = \frac{1}{2}*20*0.20^2
Ep =  \frac{20*0.04}{2}
Ep =  \frac{0.8}{2}
\boxed{\boxed{Ep = 0.4\:J}}\end{array}}\qquad\quad\checkmark
7 0
3 years ago
A government agency estimated that air bags have saved over 14,000 lives as of April 2004 in the United States. (They also state
balu736 [363]

To solve this problem it is necessary to apply the concepts related to momentum, momentum and Force. Mathematically the Impulse can be described as

I = F*t

Where,

F= Force

t= time

At the same time the moment can be described as a function of mass and velocity, that is

P = m\Delta v \rightarrow P=m(v_1-v_2)

Where,

m = mass

v = Velocity

From equilibrium the impulse is equal to the momentum, therefore

I = p

Ft = m(v_1-v_2)

PART A) Since the body ends at rest, we have the final speed is zero, so the momentum would be

p=m(v_1-v_2)

p = 75*0.15

p = 1125Kg\cdot m/s

Therefore the magnitude of the person's impulse is 1125Kg.m/s

PART B) From the equation obtained previously we have that the Force would be:

Ft = m(v_1-v_2)

F(0.025)= 1125

F= 45000N

Therefore the magnitude of the average force the airbag exerts on the person is 45000N

6 0
3 years ago
A force of 200N due South and another force of 300N due East each act on an object simultaneously.
dangina [55]

Answer:

a) 500

b)-500, north west

Explanation:

a) sum of F= F1+F2= 200+300= 500

b) sum of forces=0

so 200+300-500+0

4 0
2 years ago
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