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Fudgin [204]
2 years ago
15

What is the average speed of an object that travels 6 meters in 2 seconds and then travels 3 meters in 1 second?

Physics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Answer:

3 m/s

Explanation:

Average Speed = \frac{Total Distance}{Total time}

Plug in the numbers, it will be (6m + 3m) divided by (2s + 1s), which is 9m/3s, which equals to 3m/s.

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A transverse wave is traveling through a canal. If the distance between two successive crests is 3.17 m and four crests of the w
Thepotemich [5.8K]

Answer:

a. 0.18Hz

b. 0.56m/s

Explanation:

From the question we can deduct the following parameters

The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.

Also the period of the wave T can be computed as

T=22.6/4

T=5.65secs.

a. To compute the frequency, recall that frequency, F=1/period.

Hence,

F=1/5.65

F=0.18Hz

b. Next we compute the wave speed.

Wave speed=frequency *wavelength

Wave speed =0.18*3.17

Wave speed =0.56m/s

5 0
3 years ago
How do you think electricity was discovered
sasho [114]
Italian physicist Alessandro Volta discovered that particular chemical reactions could produce electricity, and in 1800 he constructed the voltaic pile (an early electric battery) that produced a steady electric current, and so he was the first person to create a steady flow of electrical charge.
8 0
2 years ago
Read 2 more answers
11. Velocity-time graph for the motion of an object in a straight path is a straight line parallel to the time axis
Vilka [71]

a) uniform velocity

b) zero or no acceleration

c) (see picture)

EXPLANATION:

(see picture)

8 0
2 years ago
A shadow from a surgeon's hand obstructs your view while operating. Make suggestions for an alternative light source that avoids
Charra [1.4K]

Answer:

B...................

4 0
3 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
leonid [27]

Answer:

KE_A=33\ J

KE_B=99\ J

Explanation:

Given:

Let mass of the particle B be, m_B=m

then the mass of particle A, m_A=3m

Energy stored in the compressed spring, E=132\ J

Now when the compression of the particles with the spring is released, the spring potential energy must get converted into the kinetic energy of the particles and their momentum must be conserved.

Kinetic energy:

\frac{1}{2}m_A.v_A^2+\frac{1}{2}m_B.v_B^2=132

3m.v_A^2+m.v_B^2=264 .............................(1)

<u>Using the conservation of linear momentum:</u>

m_A.v_A+m_B.v_B=0

3m.v_A+m.v_B=0 .............................(2)

Put the value of v_A from eq. (2) into eq. (1)

3m\times (\frac{-v_B}{3})^2+m.v_B^2=264

v_B^2=\frac{198}{m}  ...........................(3)

<u>Now the kinetic energy of particle B:</u>

KE_B=\frac{1}{2}\times m_B\times v_B^2

KE_B=\frac{1}{2}\times m\times \frac{198}{m}

KE_B=99\ J

Put the value of v_B^2 form eq. (3) into eq. (1):

v_A^2=\frac{22}{m}

<u>Now the kinetic energy of particle A:</u>

<u />KE_A=\frac{1}{2}m_A.v_A^2<u />

<u />KE_B=\frac{1}{2}\times 3m\times \frac{22}{m}<u />

KE_A=33\ J

6 0
3 years ago
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