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frosja888 [35]
3 years ago
5

What if you love someone a lot but are to afraid to say it?

Chemistry
2 answers:
Trava [24]3 years ago
7 0

Answer:

Go for it. You'll either figure out they love you back or they don't. if they don't love you back, it gives you the time to heal and move on the quicker you know the truth. I know this from experience.

Serjik [45]3 years ago
4 0

Answer:

Zodiac signs.

Explanation:

Cringe.

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What is the oxidation number for s in s2o4?
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The oxidation number of O is -2 and there's 4 of them so the total is -8. Since it's a molecule the sum of the oxidation numbers of the atoms must equal 0. If 4 oxygen atoms have an oxidation number of -8 then the two S atoms must is +8 to equal 0 so the oxidation number of the S is 8/2 = +4
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How many molecules are in 17 grams of sodium chloride? Show your work.
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Answer: 0.02 molecules
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No. Of moles= Molar mass of NaCI
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Read the given equation.
S_A_V [24]

Answer:

2.30 liters.

Explanation:

  • The balanced equation of the reaction is:

<em>Na₂O₂ + CO₂ → Na₂CO₃ + 1/2O₂,</em>

  • It is clear that 1.0 mole of Na₂O₂ reacts with 1.0 mole of CO₂ to produce 1.0 mole of Na₂CO₃ and 0.5 mole of O₂.
  • The no. of moles of CO₂ in (4.60 L) reacted can be calculated from the relation: <em>PV = nRT</em>.

P is the pressure of the gas (P = 1.0 atm at STP),

V is the volume of the gas (V = 4.60 L),

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the gas (T = 273.0 K at STP).

∴ n = PV/RT = (1.0 atm)(4.6 L) / (0.082 L.atm/mol.K)(273.0 K) = 0.205 mol.

<u><em>Using cross multiplication:</em></u>

1.0 mole of CO₂ produces → 0.5 mole of O₂, from the stichiometry.

0.205 mole of CO₂ produces → ??? mole of O₂.

  • The no. of moles of O₂ produced from 4.60 L of CO₂ = (0.5 mole)(0.205 mole) / (1.0 mole) = 0.103 mole.
  • ∴ The volume of O₂ produced from 4.60 L of CO₂ = nRT/P = (0.103 mol)(0.082 L.atm/mol.K)(273.0 K) / (1.0 atm) = 2.30 liters.
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"<span>A. The net force applied will increase." This is because there is more force being applied. </span>
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