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nadya68 [22]
3 years ago
11

The number ocean waves that pass a buoy in one second is _ of the wave

Physics
2 answers:
mr_godi [17]3 years ago
7 0
The number of ocean waves that pass a buoy in one second is the frequency of the <span>wave. The crest of a transverse wave is its highest point. </span>
alexgriva [62]3 years ago
4 0
Your answer is the frequency of the wave
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What does the churning air in the troposphere help determine
bogdanovich [222]
The churning air in the troposphere helps determine the altitude of a place
8 0
3 years ago
Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 Ω · m
svetoff [14.1K]

Answer:

0.34148 m

Explanation:

\rho = Resistivity of tungsten = 5.6\times 10^{-8}\ \Omega m

d = Diameter = 0.0018 inch

r = Radius = \dfrac{r}{2}=\dfrac{0.0018}{2}=0.0009\ in

r=0.0009\times 0.0254=0.00002286\ m

\alpha = Temperature coefficient of tungsten = 0.0045 /^{\circ}C

Power is given by

P=\dfrac{V^2}{R}\\\Rightarrow R=\dfrac{V^2}{P}\\\Rightarrow R=\dfrac{120^2}{100}\\\Rightarrow R=144\ \Omega

We have the equation

R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega

Resistance is given by

R=\rho\dfrac{l}{A}\\\Rightarrow l=\dfrac{RA}{\rho}\\\Rightarrow l=\dfrac{11.64812\times \pi (0.00002286)^2}{5.6\times 10^{-8}}\\\Rightarrow l=0.34148\ m

The length of the filament is 0.34148 m

7 0
3 years ago
An electromagnetic flowmeter is useful when it is desirable not to interrupt the system in which the fluid is flowing (e.g. for
AURORKA [14]

Answer:

<em>2 m/s</em>

<em></em>

Explanation:

The electromagnetic flow-metre work on the principle of electromagnetic induction. The induced voltage is given as

E = Blv

where E is the induced voltage = 2.88 mV = 2.88 x 10^-3 V

l is the distance between the electrodes in this field which is equivalent to the diameter of the tube = 1.2 cm = 1.2 x 10^-2 m

v is the velocity of the fluid through the field = ?

B is the magnetic field = 0.120 T

substituting, we have

2.88 x 10^-3 = 0.120 x 1.2 x 10^-2 x v

2.88 x 10^-3 = 1.44 x 10^-3 x v

v = 2.88/1.44 = <em>2 m/s</em>

8 0
3 years ago
A quick USB charger claims its output current is 1.97Amp. We know that the standard USB output voltage is 5V. What is the output
Arte-miy333 [17]

Answer:

Output power of the charger is 9.85 watts.

Explanation:

It is given that,

Output current of the USB charger, I = 1.97 A

The standard USB output voltage, V = 5 V

We need to find the output power of the charger. It can be determined using the following formula as :

P = V × I

P=5\ V\times 1.97\ A

P = 9.85 watts

The output power of the charger is 9.85 watts. Hence, this is the required solution.

3 0
2 years ago
Despite the gases, dust, and stars that compose the universe, it is still mostly made up of ____________________.
ivann1987 [24]

Answer:

space

Explanation:

5 0
3 years ago
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