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nadya68 [22]
3 years ago
11

The number ocean waves that pass a buoy in one second is _ of the wave

Physics
2 answers:
mr_godi [17]3 years ago
7 0
The number of ocean waves that pass a buoy in one second is the frequency of the <span>wave. The crest of a transverse wave is its highest point. </span>
alexgriva [62]3 years ago
4 0
Your answer is the frequency of the wave
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What is the critical angle of a light beam passed from a medium (n=2) to a medium (n=1.2)?
sertanlavr [38]

Answer:

θ_c = 36.87°

Explanation:

Index of refraction for index medium; n_i = 2

Index of refraction for Refractive medium; n_r = 1.2

Formula to find the critical angle is given;

n_i(sin θ_c) = n_r(sin 90)

Where θ_c is critical angle.

Thus;

2 × (sin θ_c) = 1.2 × 1

(sin θ_c) = 1.2/2

(sin θ_c) = 0.6

θ_c = sin^(-1) 0.6

θ_c = 36.87°

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3 years ago
when in object moves stop moving changes speed or changes direction how do scientist describe that condition?
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As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
Oksana_A [137]

Answer:

a.Attractive

2.31531\times 10^{-16}\ N

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Here, there is a proton and electron which are different particles hence, they will attract each other.

q_1=q_2 = Charge of electron and proton = 1.6\times 10^{-19}\ C

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k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Force is given by

F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(997\times 10^{-9})^2}\\\Rightarrow F=2.31531\times 10^{-16}\ N

The force of attraction between the particles will be 2.31531\times 10^{-16}\ N

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3 years ago
What is the acceleration of a softball if it has a mass of 0.5 kg and hits the cathers glove with a force of 25n
ioda
Acceleration is found if we have the force and mass. 

With the following equation: F = ma, we can find the missing values. 

F = 25n
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a = f/m
a = 25/0.5
a = 50

a = 50 m/s

So, the acceleration is 50 m/s^2 
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3 years ago
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