Answer:
1. C
2. D
Explanation:
<em>1</em><em>.</em><em> </em><em>as </em><em>the </em><em>object </em><em>is </em><em>stationary </em><em>despite </em><em>Jamal </em><em>applying </em><em>100N</em><em> </em><em>forces</em><em>, </em><em>it </em><em>suggests </em><em>that </em><em>the </em><em>object </em><em>i</em><em>s </em><em>applying </em><em>an </em><em>equal </em><em>amount </em><em>of </em><em>force </em><em>on</em><em> </em><em>the </em><em>opposite</em><em> </em><em>direction </em><em>that </em><em>is </em><em>opposing </em><em>the </em><em>force </em><em>applied</em><em> </em><em>by </em><em>Jamal.</em>
<em>2</em><em>.</em><em> </em><em>inertia </em><em>is</em><em> </em><em>a property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force.</em><em> </em>
<em>hope </em><em>it</em><em> helps</em><em>. </em><em>:</em><em>)</em>
The object A has the greater mass compared to object B.
<u>Explanation:
</u>
The weight of any object on any planet is the measurement of gravity’s influence acting on the mass of the object. So for Earth, the acceleration will be acting on the object A’s mass (m) in Earth leading to the weight of the object A as 750 N.
While the acceleration of Jupiter will be acting on the object B’s mass kept in Jupiter to attain the weight of 750 N. So, the mass of both the objects at their respective planet will vary depending on the acceleration of each planet. We can check this as below:

So,

Thus,

Similarly for object B,


Thus,

Thus, the mass of object A is greater than the mass of object B.
Answer:
Explanation:
Electric field due to charge at origin
= k Q / r²
k is a constant , Q is charge and r is distance
= 9 x 10⁹ x 5 x 10⁻⁶ / .5²
= 180 x 10³ N /C
In vector form
E₁ = 180 x 10³ j
Electric field due to q₂ charge
= 9 x 10⁹ x 3 x 10⁻⁶ /.5² + .8²
= 30.33 x 10³ N / C
It will have negative slope θ with x axis
Tan θ = .5 / √.5² + .8²
= .5 / .94
θ = 28°
E₂ = 30.33 x 10³ cos 28 i - 30.33 x 10³ sin28j
= 26.78 x 10³ i - 14.24 x 10³ j
Total electric field
E = E₁ + E₂
= 180 x 10³ j +26.78 x 10³ i - 14.24 x 10³ j
= 26.78 x 10³ i + 165.76 X 10³ j
magnitude
= √(26.78² + 165.76² ) x 10³ N /C
= 167.8 x 10³ N / C .
Answer:
B: Energy that is transformed is neither created or destroyed
Explanation:
Answer:
44.6 N
Explanation:
Draw a free body diagram of the block. There are four forces on the block:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing left,
and applied force F pulling right 30° above horizontal.
Sum of forces in the y direction:
∑F = ma
N + F sin 30° − mg = 0
N = mg − F sin 30°
Sum of forces in the x direction:
∑F = ma
F cos 30° − Nμ = 0
F cos 30° = Nμ
N = F cos 30° / μ
Substitute:
mg − F sin 30° = F cos 30° / μ
mg = F sin 30° + (F cos 30° / μ)
Plug in values:
mg = 20 N sin 30° + (20 N cos 30° / 0.5)
mg = 44.6 N