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musickatia [10]
3 years ago
14

The driver of a car traveling at 30.5 m/s slams on the brakes so that the car undergoes a constant acceleration, skidding to a c

omplete stop in 4.5 s. What is his average acceleration?
-2.6 m/s^2
2.6 m/s^2
6.8 m/s^2
-6.8 m/s^2
Physics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

-6.8 m/s²

Explanation:

Given:

v₀ = 30.5 m/s

v = 0 m/s

t = 4.5 s

Find: a

a = (v − v₀) / t

a = (0 m/s − 30.5 m/s) / 4.5 s

a = -6.8 m/s²

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castortr0y [4]
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5 0
2 years ago
Suppose astronomers built a 150-meter telescope. how much greater would its light-collecting area be than that of the 10-meter k
Dennis_Churaev [7]
Almost all telescopes have a circular mirror. The area of a circle is proportional to r^2 where r is the radius of the circle, the constant of proportionality being 4\pi
S =4\pi r^2
Therefore the area of 150 meter telescope would be 
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times bigger than the area of the smaller (10 meter) telescope.

6 0
2 years ago
Two electrons are initially at rest separated by a distance of 2nm. At time t=0, they start to move apart due to Coulombic repul
Gnom [1K]

Answer:

t=2.5\times 10^{-14}\ s

Explanation:

We know that charge on electron

q=1.6\times 10^{-19}\ C

r= 2 nm

We know that force between two charge given

F=K\dfrac{Q_1Q_2}{r^2}

Now by putting the value

F=9\times10^9\dfrac{1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(2\times 10^{-9})^2}

F=5.67\times 10^{-11}\ N

We know that mass of electron

The mass of electron

m=9.1\times 10^{-31}\ kg

F= m a

a= Acceleration of electron

a= F/m

a=\dfrac{5.67\times 10^{-11}}{9.1\times 10^{-31}}\ m/s^2

a=6.2\times 10^{19} m/s^2

S=ut+\dfrac{1}{2}at^2

initial velocity given that zero ,u=0

20\times 10^{-9}=\dfrac{1}{2}\times 6.2\times 10^{19} t^2

t=\sqrt {\dfrac{40\times 10^{-9}}{6.2\times 10^{19}}}

t=2.5\times 10^{-14}\ s

3 0
3 years ago
A ball rolls for 8 seconds and travels 24 meters. How fast was it traveling?
belka [17]

Answer:

The speed of the ball was, v = 3 m/s

Explanation:

Given data,

The time period of the ball, t = 8 s

The distance the ball rolled, d = 24 m

The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,

                              v = d / t      m/s

Substituting the given values in the above equation,

                               v = 24 / 8

                                  = 3 m/s

Hence, the speed of the ball was, v = 3 m/s

8 0
3 years ago
The continuous submarine mountain range which winds through all the oceans is called the mid-ocean
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The continuous submarine mountain range which winds through all the oceans is called the mid-ocean <u>ridge.
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