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True [87]
2 years ago
7

Suppose a car is traveling at +20.3 m/s, and the driver sees a traffic light turn red. After 0.207 s has elapsed (the reaction t

ime), the driver applies the brakes, and the car decelerates at 7.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light?
Physics
1 answer:
olga nikolaevna [1]2 years ago
7 0

Answer:

33.6371 m

Explanation:

t = Time taken

u = Initial velocity = 20.3 m/s

v = Final velocity

s = Displacement

a = Acceleration = -7 m/s²

Distance traveled in the 0.207 seconds

Distance = Speed × Time

⇒Distance = 20.3×0.207 = 4.2021 m

Equation of motion

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20.3^2}{2\times -7}\\\Rightarrow s=29.435\ m

Distance traveled by the car while braking is 29.435 m

Total distance measured from the point where the driver first notices the red light is 29.435+4.2021 = 33.6371 m

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A note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note​
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\huge\boxed{\sf \lambda = 2 m}

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<h3><u>Given data:</u></h3>

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\rule[225]{225}{2}

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