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Galina-37 [17]
2 years ago
8

Difference between power ciruit and light circuit?

Physics
1 answer:
Svetlanka [38]2 years ago
7 0

Refer to attachment for your answer

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Is this right?? please help me. IT IS SOCIOLOGY!!
Westkost [7]

Answer:

Yes, it is correct : )

Explanation:

Hope this helps!

8 0
2 years ago
Read 2 more answers
A mass of 250 N is on a piston of 2.0 m^2. What force is needed to lift this piston if the area of the second piston is 0.5 m^2?
prohojiy [21]

Answer:

<h3>62.5N</h3>

Explanation:

The pressure at one end of the piston is equal to the pressure on the second piston.

Pressure = Force/Area

F1/A1 = F2/A2

Given

F1 = 250N

A1 = 2.0m²

A2 = 0.5m²

F2 = ?

Substituting the given values in the formula;

250/2 = F2/0.5

cross multiply

250*0.5 = 2F2

125 = 2F2

F2 = 125/2

F2 = 62.5N

Hence the  force needed to lift this piston if the area of the second piston is 0.5 m^2 is 62.5N

8 0
3 years ago
Which of the following is a luminous object?<br> the Moon<br> Jupiter<br> a comet<br> the Sun
babunello [35]
The Sun is a luminous object. 
3 0
3 years ago
Read 2 more answers
What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a
Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity  = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2

v = r ω

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}

I = \dfrac{m(2gh - v^2)r^2}{v^2}

I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}

I =mr^2(0.287)

I = 0.287 MR²

3 0
3 years ago
When is the pressure of the man on the ground more – lying position or standing position? Explain.
Dmitrij [34]
It is without a doubt in standing position!
“I will explain if u ask”
(Please mark brainlest if I helped u a bit)
3 0
3 years ago
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