Answer:
4.41
Explanation:
Step 1: Write the balanced equation
CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)
Step 2: Calculate the respective concentrations
![[CO]_i = \frac{0.500mol}{5.00L} = 0.100M](https://tex.z-dn.net/?f=%5BCO%5D_i%20%3D%20%5Cfrac%7B0.500mol%7D%7B5.00L%7D%20%3D%200.100M)
![[H_2]_i = \frac{1.500mol}{5.00L} = 0.300M](https://tex.z-dn.net/?f=%5BH_2%5D_i%20%3D%20%5Cfrac%7B1.500mol%7D%7B5.00L%7D%20%3D%200.300M)
![[H_2O]_{eq} = \frac{0.198mol}{5.00L} = 0.0396M](https://tex.z-dn.net/?f=%5BH_2O%5D_%7Beq%7D%20%3D%20%5Cfrac%7B0.198mol%7D%7B5.00L%7D%20%3D%200.0396M)
Step 3: Make an ICE chart
CO(g) + 3 H₂(g) = CH₄(g) + H₂O(g)
I 0.100 0.300 0 0
C -x -3x +x +x
E 0.100-x 0.300-3x x x
Step 4: Find the value of x
Since the concentration at equilibrium of water is 0.0396 M, x = 0.0396
Step 5: Find the concentrations at equilibrium
[CO] = 0.100-x = 0.100-0.0396 = 0.060 M
[H₂] = 0.300-3x = 0.300-3(0.0396) = 0.181 M
[CH₄] = x = 0.0396 M
[H₂O] = x = 0.0396 M
Step 6: Calculate the equilibrium constant (Kc)
![Kc = \frac{[CH_4] \times [H_2O] }{[CO] \times [H_2]^{3} } = \frac{0.0396 \times 0.0396 }{0.060 \times 0.181^{3} } = 4.41](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BCH_4%5D%20%5Ctimes%20%5BH_2O%5D%20%7D%7B%5BCO%5D%20%5Ctimes%20%5BH_2%5D%5E%7B3%7D%20%7D%20%3D%20%5Cfrac%7B0.0396%20%5Ctimes%200.0396%20%7D%7B0.060%20%5Ctimes%200.181%5E%7B3%7D%20%7D%20%3D%204.41)
The answer is D. The cold fusion theory was first brought about by Stanley Pons and Martin Fleischmann in 1989. They claimed that their unintended experiment has produced enormous amounts energy at room temperatures that could only be explained by cold fusion theory. The experiment involved the electrolysis of heavy water (with deuterium rather than hydrogen isotope) on a palladium (Pd) electrode. Their claims had brought immense attention by scientists, however, subsequent replicative experiments attempts failed and some discredited the initial experiment.
We will use Arrehenius equation
lnK = lnA -( Ea / RT)
R = gas constant = 8.314 J / mol K
T = temperature = 25 C = 298 K
A = frequency factor
ln A = ln (1.5×10 ^11) = 25.73
Ea = activation energy = 56.9 kj/mol = 56900 J / mol
lnK = 25.73 - (56900 / 8.314 X 298) = 2.76
Taking antilog
K = 15.8
Answer:
vicobic ohffsrhnuyoekenennejjekemjdhfmkd
Answer:
a solid in a gas
Explaination:
because soild will take a long while to dissolve into liquid by heating the soild with gas it will disslove quicker
