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Nina [5.8K]
3 years ago
6

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th

e electric force on this electron due to this field? A. 1.6 × 10-3 newtons B. 1.4 × 1024 newtons C. 2.2 × 10-14 newtons D. 7.4 × 10-13 newtons E. 4.5 × 1014 newtons
***update, its not D lol
Physics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

Electric force, F=2.24\times 10^{-14}\ N

Explanation:

It is given that,

Charge on an electron is -1.6\times 10^{-19}\ C

Electric field, E=1.4\times 10^5\ N/m

We need to find the magnitude of the electric force on this electron due to this field. The electric force is given by :

F=qE\\\\F=1.6\times 10^{-19}\times 1.4\times 10^5\\\\F=2.24\times 10^{-14}\ N

So, the electric force is 2.24\times 10^{-14}\ N.

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Hey there, the answer is ..............................  About 0.7 m/sec^2
<span>
Acceleration is the change in speed / time </span>

<span>Change in speed is 60 m/sec </span>

<span>Time is 1 minute 25 second. Convert that to seconds. </span>

<span>Divide the change in speed by the time in seconds.

About 0.7 m/sec^2

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3 years ago
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
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Answer:

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V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

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The formula is x = 1/2 at^2 and I have managed to fill in the variables as this. d = 1/2 9.81 m/s^2 1^2
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Right, as you mentioned in the comments, you find d by plugging in the different values of t.

For t=1\,\mathrm s, we have

d=\dfrac12\left(9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)(1\,\mathrm s)^2

d=\left(4.905\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(1\,\mathrm s^2\right)

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Similarly, for t=2\,\mathrm s, you get

d=\dfrac12\left(9.81\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(2\,\mathrm s\right)

d=\left(4.905\,\dfrac{\mathrm m}{\mathrm s^2}\right)\left(4\,\mathrm s^2\right)

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The universe is the collection of galaxies, The Andromeda Galaxy has spectral lines with blue shift. The conclusion is that the Universe has stopped expanding.

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Therefore, this concludes that, the Universe has stopped expanding. This galaxy is slowly shifting towards us.

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2 years ago
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