The number of boxes were produced willl be 7.57.n stands for the no of boxes.
<h3>What is volume?</h3>
The term “volume” refers to the amount of three-dimensional space taken up by an item or a closed surface. It is denoted by V and its SI unit is in cubic cm.
The volume of the cylindrical metal bar;
V₁=πr²h
V₁=3.4 × 7² × 484 cm
V₁=80,634.4 cm³
The one side of the box is,220mm(22 cm)
V₂ = a³
V₂ = (22)³
V₂ = 10,648 cm³
The no of boxes is found as;
n = V₁/V₂
n=80,634.4 cm³/10,648 cm³
n=7.57
Hence, the number of boxes were produced willl be 7.57
To learn more about the volume, refer to brainly.com/question/1578538
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Answer:
(1) chess is played by him
(2) The great black engine was seen by her
(3) Arrangements for functions had been made by him
(4) A meeting is being attended by Raman
= when the last of the guests left, I went back into the hall to look for my mobile phone that I had kept on the table, I found that my mobile phone was not there. I felt freaked and I asked to every member of my family about my phone, but nobody had idea about that. then there was a phone call made by my uncle to my father, that his son had taken the mobile by mistake. After sometime, My uncle came to return my mobile. Then I took a sigh of relief .
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Answer:
v = 27.456 m/s
Explanation:
The support pressure needed of the water in the straw can be calculated by the formula
Given that,
P = r*g*h
= 1000*9.8*0.05 Pa.= 490 Pa
This pressure is compensated by 0.5*r*v^2 of the air,
Hence,
0.5*1.3*v^2 = 490
velocity of air blown into the straw =
v = 27.456 m/s
Answer:
1. the principle of original horizontality
2. the principle of crosscutting relationships
3. the law of superposition
4. older
5. younger
Answer:
As collision is elastic,thus we can use conservation of momentum equation
mA=0.2 kg
(vB)1=0 m/s.......................as it is on rest before collision
(vA)1=4 m/s
(vA)2=-1 m/s
(vB)2=2 m/s
using equation
(mA*vA+mB*vB)1= (mA*vA+mB*vB)2
Where 1 and 2 represents before and after collision
(0.2*4)+(mB*0)=(0.2*-1)+(mB*2)
0.8=-0.2+(2mB)
mass of object B=mB=0.3 Kg