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NISA [10]
3 years ago
13

A student creates a model of a closed ecosystem by filling a glass tank half full with water then adding 10 snails and two small

aquatic plants the next day all the snails are dead what is the most likely cause of their death
Physics
2 answers:
worty [1.4K]3 years ago
8 0

In any closed ecosystem, if we put some snails and some plants in them, the snails would survive for a while but next day they will die, this is because of the reason that the snails can survive for a while in closed ecosystem but the waste products which takes place in the ecosystem due to both the plants as well as the snails affects the snails due to which they are likely to die soon.

GenaCL600 [577]3 years ago
4 0
The reason why the snails are dead because the snails lack oxygen for it is a model of closed ecosystem. Another reason to this is that they lack  abiotic factors that they need in surviving or as they live for the place that they are living lacks a lot and are not enough for them to last or survive. Lastly, the water could have not been a contributor for them to live for they may not be able to live in a water environment and could only dwell in land.
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A string has its 4th harmonic at 31.5 Hz. What is the fundamental frequency?
seropon [69]

Given data

*The given 4th harmonic frequency is 31.5 Hz

The fundamental frequency is calculated as

\begin{gathered} f_n=\frac{31.5}{4} \\ =7.875\text{ Hz} \end{gathered}

Hence, the fundamental frequency is 7.875 Hz

5 0
1 year ago
A ball is thrown so that its initial vertical and horizontal components of velocity are 30 m/s and 15 m/s, respectively. Estimat
mihalych1998 [28]

Answer:

H = 45 m

Explanation:

First we find the launch velocity of the ball by using the following formula:

v₀ = √(v₀ₓ² + v₀y²)

where,

v₀ = launching velocity = ?

v₀ₓ = Horizontal Component of Launch Velocity = 15 m/s

v₀y = Vertical Component of Launch Velocity = 30 m/s

Therefore,

v₀ = √[(15 m/s)² + (30 m/s)²]

v₀ = 33.54 m/s

Now, we find the launch angle of the ball by using the following formula:

θ = tan⁻¹ (v₀y/v₀ₓ)

θ = tan⁻¹ (30/15)

θ = tan⁻¹ (2)

θ = 63.43°

Now, the maximum height attained by the ball is given by the formula:

H = (v₀² Sin² θ)/2g

H = (33.54 m/s)² (Sin² 63.43°)/2(10 m/s²)

<u>H = 45 m</u>

6 0
3 years ago
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