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Velocity
Note : Not speed as Acceleration is a vector!
Answer:
have a component along the direction of motion that remains perpendicular to the direction of motion
Explanation:
In this exercise you are asked to enter which sentence is correct, let's start by writing Newton's second law.
circular movement
F = m a
a = v² / r
F = m v²/R
where the force is perpendicular to the velocity, all the force is used to change the direction of the velocity
in linear motion
F = m a
where the force is parallel to the acceleration of the body, the total force is used to change the modulus of the velocity
the correct answer is: have a component along the direction of motion that remains perpendicular to the direction of motion
Answer:
Recessed incandescent luminaires not marked type ic and those marked for installing directly in insulated ceilings must not have insulation over the top of the luminaire.
Explanation:
Depending on how they interact with insulation, lighting fixtures are rated at various levels. Non-IC rated lighting fixtures can accommodate higher wattage bulbs, but they also pose the greatest fire risk when used with the incorrect insulation.
In locations with insulation, light fixtures that are not IC rated may be installed. But there is a condition. The distance between the fixture and any insulation should be 3 inches. But the 3 inch gap in the insulation would negate the goal of insulation by producing a lot of uninsulated space, so this defies logic. Building a box-style cover to cover the fixture on the attic side is one option to fix this. Drywall or foil-faced foam insulation can be used to create this box. After the cover is put in place, insulation can be added for maximum effectiveness.
To learn more about recessed incandescent luminaries. Click brainly.com/question/17218799
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Answer
![200km {h}^{ - 2}](https://tex.z-dn.net/?f=200km%20%7Bh%7D%5E%7B%20-%202%7D%20)
Explanation
![Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}](https://tex.z-dn.net/?f=Acceleration%20%3D%20%20%5Cfrac%7Bfinal%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20velocity%20-%20initial%20%5C%3A%20%20%5C%3A%20velocity%20%7D%7Btime%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B%2840%20-%2030%29km%20%7Bh%7D%5E%7B%20-%201%7D%20%7D%7B0.05h%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B10%7D%7B0.05%7D%20%20%5C%5C%20%20%3D%20200km%20%7Bh%7D%5E%7B%20-%202%7D%20)
Hope this helps you.
Let me know if you have any other questions :-):-)
Answer:
i) 3.514 s, ii) 5.692 m/s
Explanation:
i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.
as the equation says for free-falling
h = ut +0.5gt^2
Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)
initial velocity u = 0
10 = 0.5×1.62t^2
t = 3.514 seconds
Therefore, it takes t = 3.514 seconds for the Eagle to touch down.
ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon
v = u + gt
v = 0+ 1.62×3.514
v= 5.692 m/s