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Mariulka [41]
3 years ago
15

If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50

mi/hr?
Physics
2 answers:
Harman [31]3 years ago
6 0
a= \frac{V}{t} \ \ \ \Rightarrow\ \ a= \frac{60\ [mi/hr]}{8\ [s]} \\ \\the\ final\ speed\ after\ 5.0\ seconds\\ \\V=50\ [mi/hr]+5\ [s]\ \cdot \frac{60\ [mi/hr]}{8\ [s]}=50\ [mi/hr] + \frac{5}{8} \cdot 60\ [mi/hr]=\\ \\=50\ [mi/hr]+37.5\ [mi/hr]=87.5\ [mi/hr]
Lady_Fox [76]3 years ago
5 0
v_1=60\ \frac{mi}{h}\\\\t_1=8.0\ s=\frac{8}{3600}\ h=\frac{1}{450}\ h\\--------------\\a=\frac{v}{t}\\\\a=\frac{60}{\frac{1}{450}}\ \frac{mi}{h^2}=27000\ \frac{mi}{h^2}\\--------------\\v_o=50\ \frac{mi}{h}\\\\t=5.0\ s=\frac{5}{3600}\ h=\frac{1}{720}\ h\\--------------

v=v_o+at\\\\\\v=50\ \frac{mi}{h}+27000\ \frac{mi}{h^2}\cdot\frac{1}{720}\ h=50\ \frac{mi}{h}+37.5\ \frac{mi}{h}=87.5\ \frac{mi}{h}\leftarrow Answer

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Answer:

R / 64

Explanation:

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Now they are connected in parallel.

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A light ray moving from oil (n=1.38) into an unknown material. If the light is incident at 35 and refracts at 23, what is the in
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The index of refraction of the unknown material in which a ray of light is incident at 35° and refracted at 23° is 2.03

<h3>Snell's law</h3>

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

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<h3>How to determine the refractive index </h3>

From the question given above, the following data were obtained:

  • Index of refraction of oil (nₒ) = 1.38
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nₒSine i = nᵣSine r

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Divide both side by Sine 23

nᵣ = (1.38 × Sine 35) / Sine 23

nᵣ = 2.03

Thus, the index of refraction of the unknown material is 2.03

Learn more about Snell's law:

brainly.com/question/25758484

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2 years ago
Can you put this in your own words plz.
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Xenon can be used for things like high pressure arc lamps for motion picture projection, in high pressure arc lamps to produce ultraviolet light and photographic flashes. It is also used to help the radiation detection, for example X-ray counters.


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