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Gelneren [198K]
3 years ago
5

Write the equation for the dissociation of KOH in water. (Include states-of-matter under TSS conditions in your answer. Use the

lowest possible whole number coefficients. Remember, if a compound is dissociating in water, it must be in aqueous solution.)
Chemistry
1 answer:
Genrish500 [490]3 years ago
6 0
KOH(s) ----> K⁺(aq)+OH⁻ (aq)
s-solid,
aq - aqueous 
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Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.
Varvara68 [4.7K]

Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl           58.443 g
------------------------------  x  -------------------  =  2.52 g NaCl
                                            1 mole

4 0
2 years ago
If an atom has 12 protons 12 neutrons, and 12 electrons, what is the charge of the atom?
Evgesh-ka [11]
I think the charge is +2
Hope this helps
6 0
3 years ago
Is there such thing as a pure mixture?
prisoha [69]
Pure substances are further broken down into elements and compounds. Mixture are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule.
3 0
3 years ago
Read 2 more answers
What elements are in olive oil?
mars1129 [50]
Oxygen,hydrogen, and carbon
4 0
3 years ago
A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
taurus [48]

Answer:

The concentration the student should write down in her lab is 2.2 mol/L

Explanation:

Atomic mass of the elements are:

Na: 22.989 u

S: 32.065 u

O: 15.999 u

Molar mass of sodium thiosulfate, Na2S2O3 = (2*22.989 + 2*32.065 + 3*15.999) g/mol = 158.105 g/mol.

Mass of Na2S2O3 taken = (19.440 - 2.2) g = 17.240 g.

For mole(s) of Na2S2O3 = (mass taken)/(molar mass)

= (17.240 g)/(158.105 g/mol) = 0.1090 mole.

Volume of the solution = 50.29 mL = (50.29 mL)*(1 L)/(1000 mL)

= 0.05029 L.

To find the molar concentration of the sodium thiosulfate solution prepared we use the formula:

= (moles of sodium thiosulfate)/(volume of solution in L)

= (0.1090 mole)/(0.05029 L)

= 2.1674 mol/L

6 0
3 years ago
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