Answer:
12.8 g of must be withdrawn from tank
Explanation:
Let's assume gas inside tank behaves ideally.
According to ideal gas equation-
where P is pressure of , V is volume of , n is number of moles of , R is gas constant and T is temperature in kelvin scale.
We can also write,
Here V, T and R are constants.
So, ratio will also be constant before and after removal of from tank
Hence,
Here, and
So,
So, moles of must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of = 32 g/mol
So, mass of must be withdrawn =
Answer:
0.153M
Explanation:
57.3/97.994 (molar mass)=0.585 moles of H3PO4
.0585/3.820L=0.153M
From what i can gather it looks like d
The answer to that is mass and chemical