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1 year ago

18.74 g of P4 is reacted with 9.6 g of Cl2 balanced is P4 (s) + 6 Cl2 (g) → 4 PCl3 (l) how many PlC3 can I make?

Chemistry

1 answer:

Yanka [14]1 year ago

3 0

P4(s) + 6Cl2(g) → 4PCl3(l)

n P4 = m P4 / Mr P4

n P4 = 18.74 / 123.88

n P4 = 0.151 mol

n Cl2 = m Cl2 / Mr Cl2

n Cl2 = 9.6 / 70.9

n Cl2 = 0.135 mol

Cl2 act as limiting reactant

n PCl3 = (coef. PCl3)/(coef. Cl2) • n Cl2

n PCl3 = (4/6) • 0.135

n PCl3 = 0.09 mol

m PCl3 = n PCl3 • Mr PCl3

m PCl3 = 0.09 • 137.33

m PCl3 = 12.36 gr

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Answer: The average atomic mass of lithium is 6.9241 u.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ ....(1)

For $_3^6\textrm{Li}$ isotope:

Mass of $_3^6\textrm{Li}$ isotope = 6 u

Percentage abundance of $_3^6\textrm{Li}$ isotope = 7.59 %

Fractional abundance of $_3^6\textrm{Li}$ isotope = 0.0759

For $_3^7\textrm{Li}$ isotope:

Mass of $_3^7\textrm{Li}$ isotope = 7 u

Percentage abundance of $_3^7\textrm{Li}$ isotope = 92.41%

Fractional abundance of $_3^7\textrm{Li}$ isotope = 0.9241

Putting values in equation 1, we get:

$\text{Average atomic mass of Lithium}=[(6\times 0.0759)+(7\times 0.9241)]$

$\text{Average atomic mass of Lithium}=6.9241u$

Hence, the average atomic mass of lithium is 6.9241 u.

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2 years ago

Melamine is used for making

vodomira [7]

Answer:

Melamine is used for making tableware,cooking utensils, plates, plastic products etc.

Explanation:

Melamine is used to manufacture many products. How? Well melamine-formaldehyde resin, as it's full name, forms molecular structures that are molded, with heat, to take the shape of the items such as tableware.

After this chemical reaction takes place, the "left over" remains as plastic.

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And so, it is used in products such as cooking utensils, plates, plastic products etc.

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3 years ago

A container of a mixture of 4 gases has a total pressure of 35.7 kPa. Gas A has a partial pressure of 7.8kPa. Gas B has a partia

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Answer:

partial pressure of gas D Pd = 15.5 kPa

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As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.

P(Total) = P1+P2+P3.....

Given P(Total) = 35.7 kPa

Partial pressure of gas A Pa = 7.8 kPa

Partial pressure of gas B Pb = 3.7 kPa

Partial pressure of gas C Pc = 8.7 kPa

There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)

Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa

Therefore, partial pressure of gas D Pd = 15.5 kPa

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2 years ago

Calculate the molarity of 13.1 g of NaCl in 727 mL of solution

valentina_108 [34]

Answer:

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

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58, 5 g-----1 mol NaCl

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1000ml solution------x= (1000ml solutionx0, 224 mol NaCl)/727 ml solution

x=0,308 mol NaCl---> The solution is 0,31 molar (0,31 M)

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Phantasy [73]

I guess B is the right one......

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