P4(s) + 6Cl2(g) → 4PCl3(l)
n P4 = m P4 / Mr P4
n P4 = 18.74 / 123.88
n P4 = 0.151 mol
n Cl2 = m Cl2 / Mr Cl2
n Cl2 = 9.6 / 70.9
n Cl2 = 0.135 mol
Cl2 act as <u>limiting reactant</u>
n PCl3 = (coef. PCl3)/(coef. Cl2) • n Cl2
n PCl3 = (4/6) • 0.135
n PCl3 = 0.09 mol
m PCl3 = n PCl3 • Mr PCl3
m PCl3 = 0.09 • 137.33
m PCl3 = 12.36 gr
Explanation:
answer is in photo above
Protons/Electrons: 92
Neutrons: 140
***REMEMBER: There is always the same amount of protons and electrons. :)
Answer:
c.hg cannot be cracked for fractional distillation as there is only one of each
Alkali metal hydroxides can be used to test the identity of metals in certain salts. The colour of the precipitate will help identify the metal : Calcium hydroxide is soluble; no precipitate is formed.
