Within one period, which group has the lowest first ionization energy?

Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes stomach acid, primarily hcl, according to the reacti

Tema [17]

For every 1 molecule of Magnesium hydroxide or Mg(OH)2 there will be 2 molecules of HCl neutralized.
If molar mass of magnesium hydroxide is 58.3197g/mol, the amount of mol in 5.50 g magnesium hydroxide should be: 5.50g/ (58.3197g/mol)= 0.0943mol.
Then, the amount of HCl molecule neutralized would be: 2* 0.0943mol= 0.18861 mol

If molar mass of HCl is 36.46094 g/mol, the mass of the molecule would be: 0.18861 mol* 36.46094g/mol = 6.88grams

5 0

3 years ago

Read 2 more answers

Increasing technology addiction among the youth write a letter to editor

ruslelena [56]

Answer:

these two would help you

Explanation:

have a good day ᕕ( ᐛ )ᕗ

6 0

2 years ago

Magnetism is believed to be caused by the alignment of small, numerous sub-units called

77julia77 [94]

Answer:

Magnetism is believed to be caused by the alignment of small, numerous sub-units called : Domains

Explanation:

Domains : A magnetic domain is the region in which in which magnetic field of the atoms are grouped together and aligned.

In unmagnetized material all the magnetic Domains point in different direction.

In magnetised material (ferromagnets , antiferromagnets) , The Domains point in a particular( fixed Pattern) direction.

5 0

3 years ago

What is The cellular process that releases the energy stored in food molecules

notka56 [123]

Respiration. That is the process.

7 0

3 years ago

Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(

likoan [24]

Balanced Half reactions are:

At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

Now at Anode reaction will occur as given:

2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

At Cathode:

2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

At Cathode:

$Mn^{2+}$ + $2e^{-}$ ==> Mn (This reaction will not occur)

The deposition of solid Mn will not occur because in aqueous solution, $H^{+}$ will be reduced before $Mn^{2+}$ .

The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

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8 0

1 year ago