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astra-53 [7]
2 years ago
5

What type of bond is formed if atoms donate electrons to other atoms when the elements are combined?

Physics
1 answer:
natita [175]2 years ago
4 0
Ionic bond.

In the ionic bond one atom loses one or more electrons, leaving the atom with positive charge, and the other atom accepts those electrons standing with negative charge.
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POINTS WILL BE GIVEN!! VVV SIMPLE IF YOURE A GENIUS
insens350 [35]

Answer:

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Explanation:

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2 years ago
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A circular test track for cars has a circumference of 3.5 kmkm . A car travels around the track from the southernmost point to t
elixir [45]

Answer:

(A) Distance will be equal to 1.75 km

(B) Displacement will be equal to 1.114 km

Explanation:

We have given circumference of the circular track = 3.5 km

Circumference is given by 2\pi r=3.5

r = 0.557 km

(a) It is given that car travels from southernmost point to the northernmost point.

For this car have to travel the distance equal to semi perimeter of the circular track

So distance will be equal to =\frac{3.5}{2}=1.75km

(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track

So displacement will be equal to d = 2×0.557 = 1.114 m

8 0
3 years ago
A roller coaster car rapidly picks up speed as it rolls down a slope as it starts down the slope its speed is 4m/s but 3 seconds
Gwar [14]

Answer:

The acceleration is 6 [m/s^2]

Explanation:

We can find the acceleration of the roller coaster using the kinematic equation for uniformly accelerated motion.

v_{f} =v_{i} + a*t\\where:\\v_{f} = final velocity = 22 [m/s]\\v_{i} = initial velocity = 4 [m/s]\\t = time = 3 [s]\\

Now replacing the values we have:

a=\frac{v_{f} - v_{i} }{t} \\a=\frac{22 - 4 }{3}\\a = 6 [m/s^{2} ]

3 0
2 years ago
An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
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Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

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sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

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d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

d_2 = 17.1 \times 5.08 + \frac{1}{2}\times9.8 \times 5.08^2

d_2 = 213.31 m

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Answer:

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