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zhuklara [117]
3 years ago
13

A spring has a force constant of 570.8 N/m. Find the potential energy stored in the spring when the spring is

Physics
1 answer:
shutvik [7]3 years ago
6 0

Given that,

The force constant of a spring, k = 570.8 N/m

It is stretched 4.12 cm from the equilibrium.

To find,

The potential energy stored in the spring.

Solution,

The potential energy stored in the spring is given by the formula as follows :

E=\dfrac{1}{2}kx^2

Put all the given values,

E=\dfrac{1}{2}\times 570.8 \times (4.12\times 10^{-2})^2\\\\E=0.484 J

So, the required potential energy is 0.484 J.

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A golf ball with an initial angle of 34° lands exactly 240 m down the range on a level course.
g100num [7]

Answer:50.39 m/s,

40.46 m

Explanation:

Given

launch angle=34^{\circ}

Range=240 m

We know that Range =\frac{u^2sin2\theta }{g}

240=\frac{u^2sin(68)}{9.81}

u=50.39 m/s

(b)maximum height of projectile is given by

H=\frac{u^2sin^2\theta }{2g}

H=\frac{50.39^2(sin34)^2}{2\times 9.81}

H=40.46 m

3 0
3 years ago
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A glass rod is charged by the process of ________. *
Vedmedyk [2.9K]
Magnetism.

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7 0
3 years ago
A cell phone company relies on which kind of waves in order to provide service for its customers?
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Radio waves are what cell phone company rely on
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3 years ago
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Calculate the height of a cliff if it takes 2.35s for a rock to hit the ground when it is thrown straight up from the cliff with
ad-work [718]

Answer:

y₀ = 10.625 m

Explanation:

For this exercise we will use the kinematic relations, where the upward direction is positive.

         y = y₀ + v₀ t - ½ g t²

in the exercise they indicate the initial velocity v₀ = 8 m / s.

when the rock reaches the ground its height is zero

         0 = y₀ + v₀ t - ½ g t²

        y₀i = -v₀ t + ½ g t²

let's calculate

         y₀ = - 8  2.5 + ½  9.8  2.5²

         y₀ = 10.625 m

7 0
2 years ago
When reaching a boundary between two media (1 and 2), an incident ray is partially reflected and partially refracted. The ray is
podryga [215]

Answer: critical angle, sin^-1 (n2/n1)

Explanation: the angle of incidence at which the retracted ray makes an angle of 90° with the normal is known as the critical angle.

Snell's law defined refraction mathematically as shown below

n1 sin θi = n2 sin θr

n1 = refractive index of the first medium

n2 = refractive index of the second medium

θi = angle of incidence

θr = angle of refraction

When the refrafted ray is perpendicular to the normal, the angle of refraction (θr) is 90° hence making the angle of incidence (θi) the critical angle θc

By substituting these conditions into the Snell's law, we have that

n1 sin θc = n2 sin 90

According to trigonometry, the value of sin 90 is 1, hence we have that

n1 sin θc =n2

sin θc = n2/n1

θc = sin^-1 (n2/n1)

3 0
2 years ago
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