Question

A spring has a force constant of 570.8 N/m. Find the potential energy stored in the spring when the spring is

Answer 1

Given that,

The force constant of a spring, k = 570.8 N/m

It is stretched 4.12 cm from the equilibrium.

To find,

The potential energy stored in the spring.

Solution,

The potential energy stored in the spring is given by the formula as follows :

$E=\dfrac{1}{2}kx^2$

Put all the given values,

$E=\dfrac{1}{2}\times 570.8 \times (4.12\times 10^{-2})^2\\\\E=0.484 J$

So, the required potential energy is 0.484 J.