Question

How much heat is absorbed by 34g iron skillet its temperature rises from 12c to 24 c ?

Answer 1

Answer:

$1.84\cdot 10^5 J$

Explanation:

The heat absorbed by the piece of iron is given by:

$Q=mC_S \Delta T$

where:

m = 34 g is the mass of the piece of iron

$C_s = 450 J/g^{\circ}C$ is the specific heat of iron

$\Delta T=24 C-12 C=12^{\circ}C$ is the variation of temperature of the piece of iron

Substituting numbers into the formula, we find

$Q=(34 g)(450 J/gC)(12 C)=1.84\cdot 10^5 J$