Ask question

Ask question

All categories

Vera_Pavlovna [14]

3 years ago

13

How much heat is absorbed by 34g iron skillet its temperature rises from 12c to 24 c ?

1 answer:

Mrrafil [7]3 years ago

7 0

Answer:

$1.84\cdot 10^5 J$

Explanation:

The heat absorbed by the piece of iron is given by:

$Q=mC_S \Delta T$

where:

m = 34 g is the mass of the piece of iron

$C_s = 450 J/g^{\circ}C$ is the specific heat of iron

$\Delta T=24 C-12 C=12^{\circ}C$ is the variation of temperature of the piece of iron

Substituting numbers into the formula, we find

$Q=(34 g)(450 J/gC)(12 C)=1.84\cdot 10^5 J$

You might be interested in

Describe the importance of SI units?

anyanavicka [17]

SI unit is an international system of measurements that are used universally in technical and scientific research to avoid the confusion with the units. Having a standard unit system is important because it helps the entire world to understand the measurements in one set of unit system.

5 0

3 years ago

Read 2 more answers

You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t

kati45 [8]

Answer:

The coefficient of kinetic friction $\mu_k = 0.724$

Explanation:

From the question we are told that

The length of the lane is $l = 36.0 \ m$

The speed of the truck is $v = 22.6\ m/s$

Generally from the work-energy theorem we have that

$\Delta KE = N * \mu_k * l$

Here N is the normal force acting on the truck which is mathematically represented as

$\Delta KE$ is the change in kinetic energy which is mathematically represented as

$\Delta KE = \frac{1}{2} * m * v^2$

=> $\Delta KE = 0.5 * m * 22.6^2$

=> $\Delta KE = 255.38m$

$255.38m = m * 9.8 * \mu_k * 36.0$

=> $255.38 = 352.8 * \mu_k$

=> $\mu_k = 0.724$

6 0

3 years ago

An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elect

beks73 [17]

Answer:

Speed of the alpha particle is $v=1.8180\times 10^3m/sec$

Explanation:

We have given charge on alpha particle $q=3.2\times 10^{-19}C$

Mass of the alpha particle $m=6.68\times 10^{-27}kg$

Potential difference $V=-3.45\times 10^{-3}volt$

We have to find the speed of the alpha particle

From energy conservation we know that

$\frac{1}{2}mv^2=qV$

$\frac{1}{2}\times 6.68\times 10^{-27}\times v^2=3.2\times 10^{-19}\times 3.45\times 10^{-3}$

$v=1.8180\times 10^3m/sec$

4 0

3 years ago

Calculate the horizontal force that must be applied to a 1,300 kg vehicle to give it an acceleration of 2.6 m/s² on a level road

ANEK [815]

The answer is 3,380 N

4 0

3 years ago

Newton’s first law relates motion to balanced and unbalanced forces.

BlackZzzverrR [31]

True, an object at rest stays and rest and an object in motion stays in motion

8 0

3 years ago

Read 2 more answers