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3 years ago

How much heat is absorbed by 34g iron skillet its temperature rises from 12c to 24 c ?

Physics

1 answer:

Mrrafil [7]3 years ago

7 0

Answer:

$1.84\cdot 10^5 J$

Explanation:

The heat absorbed by the piece of iron is given by:

$Q=mC_S \Delta T$

where:

m = 34 g is the mass of the piece of iron

$C_s = 450 J/g^{\circ}C$ is the specific heat of iron

$\Delta T=24 C-12 C=12^{\circ}C$ is the variation of temperature of the piece of iron

Substituting numbers into the formula, we find

$Q=(34 g)(450 J/gC)(12 C)=1.84\cdot 10^5 J$

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3 years ago

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3 years ago

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Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t

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Answer:

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

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$\phi_0 = \frac{\pi}{2}$

so we have

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

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3 years ago