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Artist 52 [7]
3 years ago
6

A ball is dropped from a height of 16 feet. Each time it drops h feet, it rebounds 0.81h feet. Find the total distance traveled

by the ball.
Physics
1 answer:
NeTakaya3 years ago
7 0
The first drop makes the ball travel 16 m.
Then the maximum height decreases to 16 x 0.81
And the distance traveled is twice the distance traveled.
If we make a pattern, this forms a geometric progression in which the common ratio is 0.81 and the first term is 16.
The sum of this series: a / (1 - r)
= 16 ( 1 - 0.81)
= 84 feet
This is the upward height, and the ball returns every time so:
Total distance = 84 x 2
= 168 feet
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A book weighing 5 N rests on top of a table. 1) A downward force of magnitude 5 N is exerted on the book by the force of
andreev551 [17]

Answer:

1) A downward force of magnitude 5 N is exerted on the book by the force of of gravity

2) An upward force of magnitude 5 N is exerted on the book by the table

Explanation:

First of all, any object near the Earth's surface experiences the forces of gravity, which is also called weight of the object. This force always acts downward.

For the book in the problem, the magnitude of the weight is 5 N.

We also know that the book is at rest: this means that the net force acting on it is zero, and there must be another force balancing the weight, in order to give a zero net force. This other force is the reaction force exerted by the table on the book: the magnitude of this force must be equal to the force of gravity (so, 5 N) and its direction is opposite to the weight, therefore upward.

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3 years ago
What waves travel through a medium? Transverse, longitudinal, surface, electromagnetic, and mechanical are the choices
Svetach [21]
Mechanical Waves require a medium to travel through in order to transport their energy from one location to another.
Hoped this helped!
6 0
3 years ago
Help me please, ;) I could use it
erastova [34]

Answer:

The solution(s) are in order with respect to the attachments

2.613\:\cdot10^5 Joules ; 5. Adding the same amount of heat to two different objects will produce the same increase in temperature ; 2. Same speed in both ; 2. A

Explanation:

Diagram 1 ( Liquid Nitrogen ) : So as you can see, we want our units in Joules here, and can therefore multiply the mass of gaseous nitrogen and the latent heat of liquid nitrogen, to cancel the units kg, and receive our solution - in terms of Joules. Let's do it.

q ( energy removed ) = mass of nitrogen * latent heat of liquid nitrogen,

q = 1.3 kg * 2.01 * 10⁵ J / kg = 1.3\:\cdot \:2.01\:\cdot \:\:10^5 = 10^5\cdot \:2.613 = 100000\cdot \:2.613 = 261300 Joules = 261.3 kiloJoules = 2.613 * 10⁵Joules is the energy that must be removed

Diagram 2 : The same amount of heat does not necessarily mean the same increase in temperature for two different objects. The increase in temperature depends on the specific heat capacity of the substance. Therefore your solution is 5 ) Adding the same amount of heat to two different objects will produce the same increase in temperature.

Diagram 3 : The temperatures in both glasses are the same, and hence the molecules have the same average speed. Therefore your solution is 2 ) Same speed in both.

Diagram 4 : Glass A has more water molecules, and hence has more thermal energy. Your solution is 2 ) A.

7 0
3 years ago
Read 2 more answers
Part b suppose the magnitude of the gravitational force between two spherical objects is 2000 n when they are 100 km apart. what
kobusy [5.1K]
<span>b) The force with a distance of 150 km is 889 N c) The force with a distance of 50 km is 8000 N This question looks like a mixture of a question and a critique of a previous answer. I'll attempt to address the original question. Since the radius of the spherical objects isn't mentioned anywhere, I will assume that the distance from the center of each spherical object is what's being given. The gravitational force between two masses is given as F = (G M1 M2)/r^2 where F = Force G = gravitational constant M1 = Mass 1 M2 = Mass 2 r = distance between center of masses for the two masses. So with a r value of 100 km, we have a force of 2000 Newtons. If we change the distance to 150 km, that increases the distance by a factor of 1.5 and since the force varies with the inverse square, we get the original force divided by 2.25. And 2000 / 2.25 = 888.88888.... when rounded to 3 digits gives us 889. Looking at what looks like an answer of 890 in the question is explainable as someone rounding incorrectly to 2 significant digits. If the distance is changed to 50 km from the original 100 km, then you have half the distance (50/100 = 0.5) and the squaring will give you a new divisor of 0.25, and 2000 / 0.25 = 8000. So the force increases to 8000 Newtons.</span>
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3 years ago
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The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This
erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

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g = \frac{GM}{(d-R_{CM})^2}

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g = \frac{GM}{(d-R_{CM})^2}

g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}

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PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

\omega = \frac{2\pi}{T}

At the same time we have that centripetal acceleration is given as

a_c = \omega^2 r

Replacing

a_c = (\frac{2\pi}{T})^2 r

a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)

a_c = 3.34*10^{-5}m/s^2

3 0
3 years ago
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