<u>Markup . . . </u>
-- I buy a cabbage for $1.00 and put it on the shelf in my store.
-- I mark it up 100% . . . I offer it for sale for $2.00
-- I mark it up 200% . . . I offer it for sale for $3.00 .
<u>Markdown . . .</u>
-- I buy a cabbage for $1.00 and put it on the shelf in my store.
-- I mark it down 100% . . . I sell it for zero. (I give it away.)
-- I mark it down 200% . . . I give you $1.00 to take it home with you.
If a line is parallel to another it has the same slope. Since the equation y = 1/3x +8 is parallel to the line we are trying to find, our second line will have the slope of 1/3x as well
This is the equation of a line:
y = mx + b
m = slope = 1/3x
b = y intercept = unknown
We have to find b to make this equation complete. How do we do this?
First plug what you know into the equation: y = 1/3x + b
Second we must solve for b. To do this plug a point that passes through the line (in this case they said (6, -2) passes through the line) into the x and y of the equation:
-2 = 1/3(6) + b
Now solve for b!
-2 = 6/3 + b
-2 = 2 + b
- 2 - 2 = b
-4 = b
The equation parallel to y=1/3x + 8 and passes through point (6, -2) is y = 1/3x - 4
The image below is the two line one a coordinate plane. As you can see, they are parallel to each other
Hope this helped!
Substitute x for 3 & y for -2
22 - 2(-2) = 26
3(2) + 2(-2) = 2
We are basically given most of what we need to calculate the height of the cannonball.
We use the formula h = –16t+ vt + s to find the height requested.
Let v = 160
Let s = 10
Let t = time in seconds
Was the value of t included? We need to know t to plug into our formula.
You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.