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Ede4ka [16]
3 years ago
9

( I will give a brainliest )

Physics
1 answer:
True [87]3 years ago
4 0

Answer:

The answer is temperature lol

Explanation:

:)

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Proved that<br>V = u+at<br>​
kondaur [170]

Answer:

\sf Proof \ below

Explanation:

We know that acceleration is change in velocity over time.

\sf a=\frac{\triangle v}{t}

\sf a=\frac{v-u}{t}

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

\sf at=v-u

Add u to both sides.

\sf at + u=v

3 0
3 years ago
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You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

burst when it hits the ground is 12 meters.

We consider that the 12 meters is the maximum height, so the velocity

at this height is zero.

To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
In this section of a circuit, a current of 2.5 A flows across R2. Find the current that flows across R3. Let R1= 3.0 ohm, R2= 8.
kolbaska11 [484]
D. 5.0A because this is right and will lead to the right answer okay you got this girl letssssss goooo googoggo Gogol
5 0
3 years ago
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The acceleration due to gravity on the moon is 1.6 m/s2. What is the gravitational potential energy of a 1200-kg lander resting
Monica [59]
Gravitational potential energy<span> is </span>energy<span> an object possesses because of its position in a </span>gravitational<span> field. </span><span>The equation for </span>gravitational potential energy<span> is GPE = mgh. 

GPE = 1200(1.6)(350) = 672000 J

Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
Read 2 more answers
If you double the voltage in a circuit and reduce the resistance by a factor of four what will happen to the current? A) it will
KatRina [158]
By Ohm's Law, we can relate current, voltage and resistance. It is expressed as V=IR. That is, there is a direct relationship between voltage and resistance and voltage and current.

V = IR
V1/2V1 = I1R1 / I2R1/4
1/2 = 4I1/I2
I2 = 8I1

Therefore, <span> it will increase by a factor of 8. Hope this answers the question.</span>
5 0
3 years ago
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