The final speed of the orange is 7.35 m/s
Explanation:
The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration  towards the ground. So we can use the following suvat equation:
 towards the ground. So we can use the following suvat equation:

where
v is the  final velocity
u is the initial velocity
a is the acceleration
t is the time elapsed
For the orange in this problem, we have
u = 0 (it is dropped from rest)
 is the acceleration
 is the acceleration
Substituting t = 0.75 s, we find the final velocity (and speed) of the orange:

Learn more about free fall:
brainly.com/question/1748290
brainly.com/question/11042118
brainly.com/question/2455974
brainly.com/question/2607086
#LearnwithBrainly
 
        
             
        
        
        
C. element only one substance
        
                    
             
        
        
        
The french revolution led to many deaths and impacted history because of the amount of life lost
        
             
        
        
        
Answer:
15.3 s and 332 m 
Explanation:
With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon
     gm = 1/6 ge
     gm = 1/6  9.8 m/s² = 1.63 m/s²
We calculate the range
     R = Vo² sin 2θ  / g
     R = 25² sin (2 30) / 1.63
     R= 332 m
We will calculate the time of flight,
    Y = Voy t – ½ g t2  
    Voy = Vo sin θ
 
When the ball reaches the end point has the same initial  height Y=0
0 = Vo sin  t – ½  g t2
0 = 25 sin (30)  t – ½ 1.63 t2
0= 12.5 t –  0.815 t2
We solve the equation
0= t ( 12.5 -0.815 t)
  t=0 s
 t= 15.3 s
The value of zero corresponds to the departure point and the flight time is 15.3 s
Let's calculate the reach on earth
R2 = 25² sin (2 30) / 9.8
R2 = 55.2 m
R/R2 = 332/55.2
R/R2 = 6
Therefore the ball travels a distance six times greater on the moon than on Earth