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nordsb [41]
3 years ago
10

How does electrical conduction compare between metals, nonmetals, and metalloids

Physics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

metal> metalloids >nonmetals    (Electrical conductivity)

Explanation:

Electrical conductivity of objects can be compared by the bonding energy of electrons in them.

Metals have less bonding energy of electrons, so even at room temperature their are significant number of free electrons to carry electrical current.

Nonmetals have a very high bonding energy of electrons, so  at room temperature negligible number of free electrons are present so electrical conductivity is very low.

Metalloids have both metallic and non metallic features. The electron bonding energy falls in between that of metals and nonmetals. So electrical conductivity also lies in between metals and nonmetals.

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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7\times 10^{10} m

v_i=9.5\times 10^4 m/s

d_2=6\times 10^{12} m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}

\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

Where mass of sun=M=1.98\times 10^{30} kg

G=6.7\times 10^{-11}

v_f=58515.9 m/s

4 0
3 years ago
Please help I will mark brainliest!!
STatiana [176]
Heat makes things expand, so in hot water the ballon will get bigger
4 0
2 years ago
Read 2 more answers
What is the average total energy density in electromagnetic radiation that has an intensity of 475 W/m^2?
Andreas93 [3]

Answer:

1.6 x 10⁻⁶ J/m³

Explanation:

I = Intensity of electromagnetic radiation = 475 Wm⁻²

U = average total energy density of electromagnetic radiation

c = speed of electromagnetic radiation = 3 x 10⁸ m/s

Intensity of electromagnetic radiation is given as

I = Uc

Inserting the values

475 = U (3\times 10^{8})

U = 1.6 x 10⁻⁶ J/m³

5 0
3 years ago
As a cold air mass advances on a warm air mass, what usually comes before it?​
Marina CMI [18]

Answer: A cold front occurs when a cold air mass advances into a region occupied by a warm air mass. If the boundary between the cold and warm air masses doesn't move, it is called a stationary front.

Explanation: Two types of occluded front exist: the warm-type and the cold-type. They’re distinguished by the relative temperatures of the air mass ahead of the occlusion – in other words, the air mass ahead of the original warm front – and the air mass behind the cold front. If the air behind the cold front is colder than the air ahead of the occlusion, it shoves beneath that air (because it’s denser) to form a cold-type occluded front. If the air behind the cold front is warmer than the air ahead, it rides over it to form a warm-type occluded front – which appears to be the more common case. In either situation, the lighter warm air representing the air mass originally between the warm and cold fronts sits above the boundary between the two cooler air masses.

Hope this helps!!

8 0
3 years ago
The ends of a magnet where the force is strongest are magnetic
professor190 [17]

Answer:

Yes

Explanation:

Its a magnet that is magnetic

3 0
3 years ago
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