Answer:
Explanation:
First, It's important to remember F = ma, and in this problem m = 13.3 kg
This can be reduced to a simple system of equations problem. Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them. So let's call them F1 and F2, with F1 arger than F2. Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.
Can you solve this system of equations seeing them like this, or do you need more help?
Explanation:
Given that,
Capacitor
Resistor
Peak voltage = 5.10 V
(A). We need to calculate the crossover frequency
Using formula of frequency
Where, R = resistor
C = capacitor
Put the value into the formula
(B). We need to calculate the when
Using formula of
Put the value into the formula
(C). We need to calculate the when
Using formula of
(D). We need to calculate the when
Using formula of
Hence, This is the required solution.
Complete Question
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.)
mm/s
Answer:
The drift velocity is
Explanation:
From the question we are told that
The current on the copper is
The cross-sectional area is
The number of copper atom in the wire is mathematically evaluated
Where is the density of copper with a value
is the Avogadro's number with a value
Z is the molar mass of copper with a value
So
Given the 1 atom is equivalent to 1 free electron then the number of free electron is
The current through the wire is mathematically represented as
substituting values
=>
Answer:
27.5 days
0.92 month
Explanation:
= radius of the orbit of moon around the earth =
= Mass of earth =
= Time period of moon's motion
According to Kepler's third law, Time period is related to radius of orbit as
inserting the values, we get
we know that
1 day = 24 hours = 24 x 3600 sec = 86400 s
1 month = 30 days