Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
<u>v₂ = 4.2 m/s</u>
<u></u>
b)
We will use the law of conservation of momentum here:
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
<u>v₂ = 5 m/s</u>
The energy of its motion is its kinetic energy.
The energy of its position is its potential energy.
Together, I think they're the object's mechanical energy.
The time of motion of the ball from the vertical height is independent of the horizontal velocity.
Horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.
The time of motion of ball dropped from a vertical height is calculated as follows;
where;
- <em>h </em><em>is the vertical height</em>
- <em>t </em><em>is the </em><em>time </em><em>of motion</em>
- <em>g </em><em>is acceleration due to gravity</em>
- <em />
<em> is the initial </em><em>vertical velocity</em>
From the equation above, we can conclude that time of motion of the ball from the vertical height is independent of the horizontal velocity.
If there is variation in drop time, it could be as a result of applied force when the ball is dropped. This applied force influences the initial velocity which in turn alters the drop time.
Generally, horizontal moving projectiles is not affected by gravity and the initial velocity is equal to the final velocity.
Learn more about horizontal and vertical velocity here: brainly.com/question/14354319
Answer:
The correct option is;
B Move both the balloon and mass 10 cm to the right
Explanation:
Given that the system is in equilibrium, we have;
Force of balloon = 
↑
Force of mass = 
↓
The direction of the balloon is having an upward motion which gives a clockwise moment or motion to the rod while the direction of the force of the mass weight is downwards, giving the rod an anticlockwise moment
for the rod to rotate clockwise, the moment of the balloon should be larger than that of the rod
At the present equilibrium we have;
× 30 = × 20
Therefore;
= 1.5×
Moving both balloon and mass 10 cm to the right gives;
The moment of the balloon = × (30 - 10) = × 20 = 20×,
The moment of the mass = × (20 - 10) = × 10
When we substitute = 1.5× in the moment equation for the mass, we have;
The moment of the mass = × 10 = 1.5× ×10 = 15×
Therefore, the balloon now has a larger momentum than that of the mass and the rod will rotate clockwise.
Answer:
There is no change in distance
Explanation:
Given that block slides a distance dd with initial velocity 
Work energy theorem states that Work done W is the difference between final kinetic energy 
and initial kinetic energy 
W = - ...........(equation 1)
In the given problem, the work is done by frictional force
Hence the work done is given by
= -
x dd
is negative since it is resistive force and dd is the distance
= - μ mg X dd
where μ is coefficient of friction.
Also we know that Kinetic energy KE = 
= 0 since final velocity is zero
= 
Substituting the corresponding values equation 1 becomes
-μ mg x dd = 0 -
dd= 
x (1/μ) ........... (equation 2)
To find distance when mass of block is doubled and initial velocity is not changed:
Equation 2 shows that the distance dd is independent of mass, therefore there is no change in distance.
